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nirvana33 [79]
2 years ago
3

Need to know answer as soon as possible please!

Mathematics
1 answer:
Elena L [17]2 years ago
5 0

4x - 5y = 1     Subtract 4x from both sides

4x - 4x  - 5y = 1 - 4x

- 5t = 1 - 4x     Or more conventionally

-5x = -4x + 1    Divide by - 5

y = -4x/-5 + 1/-5

y = (4/5) x - 1/5  


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A train traveled 260 miles in 4 hours. If the train’s average rate of travel increases by 12 mph, what is its new average rate o
jasenka [17]

Answer:

Correct option A

Step-by-step explanation:

Average rate = 260/4 = 65 mph

It increases by 12mph

So 65+12 = 77 mph

Correct option A

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How many solutions are there to the system of equations?
hichkok12 [17]

Answer: The system of equations has NO SOLUTION.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Given the following system of equations:

\left \{ {{4x-5y=5} \atop {-0.08x+0.10y=0.10}} \right.

Write the first equation and solve for "y" in order to express it in Slope-Intercept form:

4x-5y=5\\\\-5y=-4x+5\\\\y=\frac{-4x}{-5}+\frac{5}{-5}\\\\y=0.8x-1

You can identify that:

m=0.8\\b=-1

Apply the same procedure with the second equation. Then:

-0.08x+0.10y=0.10\\\\0.10y=0.08x+0.10\\\\y=\frac{0.08x}{0.10} +\frac{0.10}{0.10}\\\\y=0.8x+1

You can identify that:

m=0.8\\b=1

The slopes of both lines are equal, therefore  the lines are parallel and the system has NO SOLUTION.

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A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

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<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

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