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Gwar [14]
2 years ago
10

If 2 pounds of carrots cost $1.59,how much would 7 pounds of carrots cost?

Mathematics
2 answers:
valkas [14]2 years ago
5 0

Solution:

Given that, 2 pounds of carrots cost $1.59,

then , to find the cost of 7 pound carrots, solve it by unitary method,

first calculate the cost of 1 pound carrot.

2 pound costs $1.59

then, 1 pound will cost \frac{1.59}{2}

Now , Multiply 7 to the cost of 1 pound carrot to get the cost of 7 pound carrot

= 7*\frac{1.59}{2}= \frac{1119}{200}  = 5.56

Hence, If 2 pounds of carrots cost $1.59,then 7 pounds of carrots would cost $5.56

DanielleElmas [232]2 years ago
3 0
The correct answer would be $7.53
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frosja888 [35]

Answer:

Yes, Nadiya is correct. By multiplying the numerator and denominator by 2, the first fraction equivalent to 2/10 is 4/20.

Step-by-step explanation:

To find a fraction equivalent to 2/10, we need to multiply (or divide) the numerator and denominator by the same nonzero whole number.

As we need an equivalent fraction with a denominator greater than 10, we will need to multiply and not divide.

The first nonzero whole number we have is 1. If we multiply the numerator and denominator by 1, we get 2/10. Obviously, 2/10 is equivalent to 2/10 but the denominator is not greater than 10, so it doesn't help us.

The next whole number is 2. When we multiply the numerator and denominator by 2, we get 4/20. The denominator is not less than 20.

If we keep going, we will get 6/30, 8/40 and so on.  

Therefore, Nadiya is correct.

The correct answer is the first one.

8 0
2 years ago
Read 2 more answers
Doris ran 2.5 kilometers, then sprinted 300 meters and finally walked 1 4 of the distance she sprinted. How many meters did she
mr Goodwill [35]

Answer:

She traveled a total of 2875 metres during practice.

Step-by-step explanation:

Doris ran 2.5 kilometres, then sprinted 300 meters and finally walked 1/4 of the distance she sprinted.

To find the total distance that she traveled, we simply add the distance that she ran, sprinted and walked.

We will convert all distances to metres.

She ran 2.5 kilometres:

1 km = 1000 m

2.5 km = 2.5 * 1000 = 2500 m

So, she ran 2500 m.

She sprinted 300 m.

Se walked 1/4 the distance that she sprinted:

1/4 * 300 = 75 m

She walked 75 m.

Therefore, the total distance she traveled is:

2500 + 300 + 75 = 2875 m

She traveled a total of 2875 metres during practice.

5 0
2 years ago
Makayla has $8 to buy tickets at the school fair. Each ticket costs @1.5. Which inequality best represents how many tickets she
cricket20 [7]

Answer:

n\le 5

Step-by-step explanation:

Let n be the number of tickets Makaya has to buy.

If the cost of one ticket is $1.5, then the cost of n tickets is $1.5n.

Makayla has $8 to buy tickets at the school fair, thus

1.5n\le 8\\ \\n\le \dfrac{8}{1.5}\\ \\n\le \dfrac{80}{15}\\ \\n\le \dfrac{16}{3}\\ \\n\le 5\dfrac{2}{3}

The maximum number of tickets Makaya can buy is 5, so

n\le 5

5 0
2 years ago
Suppose that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 poi
AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A)P(X>135) = \\P(Z>0.625)\\=0.0266

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and Var (x-y)=Var(x)+Var(y) = 19

P(X-Y)>5\\\\=1-0.00029\\=0.9997

C) For a group of 3, average has std deviation = \frac{11}{\sqrt{3} } \\=6.351

P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856

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2 years ago
Determine if this conjecture is true. If not, give a counterexample. The difference of two negative numbers is a negative number
Orlov [11]

That would be a false statement

6 0
2 years ago
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