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prohojiy [21]
2 years ago
6

the product of two numbers is 450. the first number is half the second number. which equation can be used to find x, the greater

number?
Mathematics
2 answers:
Hunter-Best [27]2 years ago
4 0
Xy = 450

y = x/2 => x=2y  substituted inside first equation will get 2y*y=450 => y^2 = 225

y=15 because 15*15=225

x=2y so x=2*15 = 30 

x=30
y=15

hope this will help you 
Ilia_Sergeevich [38]2 years ago
3 0

Answer:

\frac{1}{2}y\cdot y=450

Step-by-step explanation:

Let x represent 1st number and y represent 2nd number.

We have been given that the product of two numbers is 450. We can represent this information in an equation as:

x\cdot y=450...(1)

We are also told that the first number is half the second number. We can represent this information in an equation as:

x=\frac{1}{2}y...(2)

To solve for greater number ,y, we will substitute equation (2) in equation (1) as:

\frac{1}{2}y\cdot y=450

Therefore, our required equation would be \frac{1}{2}y\cdot y=450.

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The given scenario above is like a geometric sequence with r or common ratio being 1.05 and the first term being 31 square meters. The nth term of the sequence is calculated through the equation,
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Substituting,
                        A15 = (31)(1.05)^(15 - 1) = 61.3778 square meter
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6 0
2 years ago
Tyra is laying down square carpet pieces in her photography studio. Each square carpet piece is 1 yard by 1 yard. If Tyra's phot
irakobra [83]
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Number needed = 28 
3 0
2 years ago
At Pizza Perfect, Ron and Harold make pizza crusts. When they work separately Ron finishes the job of making 100 crusts 1.2 hour
Arada [10]

Answer:  Ron take approximately 4.2 hours to make 100 crusts alone.

Step-by-step explanation:

Since we have given that

Number of hours taken by Ron before Harold = 1.2 hours

Number of hours taken by Ron and Harold together = 1.8 hours

We need to find the number of hours taken by Ron alone i.e. 'x'.

Let number of hours taken by Harold alone be '1.2-x'.

Let work done by Ron alone  = \dfrac{1}{x}

Work done by Harold = \dfrac{1}{x-1.2}

According to question, we get that

\dfrac{1}{x}+\dfrac{1}{x-1.2}=\dfrac{1}{1.8}\\\\\dfrac{x-1.2+x}{x(x-1.2)}=\dfrac{1}{1.8}\\\\\dfrac{2x-1.2}{x^2-1.2x}=\dfrac{1}{1.8}\\\\3.6x-2.16=x^2-1.2x\\\\x^2-1.2x-3.6x+2.16=0\\\\x^2-4.8x+2.16=0\\\\x=0.5,4.2

x-1.2 does not satisfied with x = 0.5 so, x = 4.2

Hence, Ron take approximately 4.2 hours to make 100 crusts alone.

7 0
2 years ago
2 sandwiches and 3 croissants costs £11.
valentina_108 [34]

Answer:

The price of a sandwich is £2.5 and the price of a croissant is £2

Step-by-step explanation:

Let s be the number of sandwiches and c be the number of croissants

Then according to given statements the equations will be:

2s+3c = 11\ \ \ \ \ \ \ Eqn\ 1\\3s+6c =19.50\ \ \ Eqn\ 2

Multiplying equation 1 by 2 and subtracting equation 2 from the new equation

2(2s+3c) = 11*2\\4s+6c = 22

Now

4s+6c-(3s+6c) = 22-19.50\\4s+6c-3s-6c = 2.5\\s = 2.5

Putting s=2.5 in equation 1

2(2.5)+3c = 11\\5+3c = 11\\3c = 11-5\\3c = 6\\\frac{3c}{3} = \frac{6}{3}\\c = 2

Hence,

The price of a sandwich is £2.5 and the price of a croissant is £2

5 0
1 year ago
Three students A, B, and C are enrolled in the same class. Suppose that A attends class 30 percent of the time, B attends class
Dvinal [7]

Answer:

(a) 0.93

(b) 0.38

Step-by-step explanation:

A attends class 30% of the time, so DO NOT attend 70%

B attends class 50% of the time, so DO NOT attend 50%

C attends class 80% of the time, so DO NOT attend 20%

Writing as probabilities:

P(A) = 0.30 and P(A') = 0.70

P(B) = 0.50 and P(B') = 0.50

P(C) = 0.80 and P(C') = 0.20

(a) the probability that at least one of them will be in class on a particular day

Let's call Q the event of none of them be in class on a particular day

Probability of at least one be in class is the complement of none of them be there, so: 1 - P(Q)

P(Q) = 0.7*0.5*0.2 = 0.07

1 - P(Q) = 1 - 0.07 = 0.93

(b) the probability that exactly one of them will be in class on a particular day?

One of them exactly be in class is

A is B not C not or A not B is C not or A not B not and C is, so

P(A).P(B').P(C') + P(A').P(B).P(C') + P(A').P(B').P(C)

0.3*0.5*0.2 + 0.7*0.5*0.2 + 0.7*0.5*0.8 =

0.03 + 0.07 + 0.28 = 0.38

4 0
2 years ago
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