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luda_lava [24]
2 years ago
4

The center of a circle is at the origin on a coordinate grid. The vertex of a parabola that opens upward is at (0,9). If the cir

cle intersects the parabola at the parabola's vertex, which statement must be true?
A. The maximum number of solutions is one

B. The maximum solutions is three

C. The circle has a radius equal to 3

D. That circle as a radius less than 9
Mathematics
2 answers:
vampirchik [111]2 years ago
8 0

Answer:

A. the maximum number of solutions is one

Step-by-step explanation:

The center of the circle is given as (0,0)

The parabola opens up and intersects the circle at its vertex (0,9).

The number of solutions is determined by the points the parabola and the circle is intersecting .Since the parabola is intersecting the circle at only one point at the parabola vertex that is (0,9) hence the maximum number of solution is one .

Option A is the right answer.

nikklg [1K]2 years ago
7 0

A. the maximum number of solutions is one

Since the circle and parabola intersect at (0, 9 ) this is the only solution there is, as the parabola opens upward away from the circle.



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Planes X and Y and points J, K, L, M, and N are shown. Vertical plane X intersects horizontal plane Y. Point L is on the left ha
____ [38]

Answer:

  1

Step-by-step explanation:

Three points define 1 plane.

7 0
2 years ago
Translate and solve: Three more than the difference of 6s and 5s is equal to the difference of 1/12 and 1/6
PilotLPTM [1.2K]

Answer:

a. (6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. s=-\frac{37}{12}

Step-by-step explanation:

You need to remember that:

1. The word "more" indicates Addition.

2. The "Difference" is the result of a Subtraction.

a. Then, knowing this information, you know that:

- "The difference of 6s and 5s" must be expressed as:

6s-5s

- Then, "Three more than the difference of 6s and 5s " is:

(6s-5s)+3

- "The difference of  \frac{1}{12} and \frac{1}{6} " can be expressed in this form:

\frac{1}{12}-\frac{1}{6}

Therefore, "Three more than the difference of 6s and 5s is equal to the difference of  \frac{1}{12} and \frac{1}{6} " is:

(6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. Solve for "s" in order to find its value:

s+3=-\frac{1}{12}\\\\12(s+3)=-1\\\\12s+36=-1\\\\12s=-1-36\\\\s=-\frac{37}{12}

8 0
2 years ago
a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r
galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

4 0
2 years ago
What is the decibel level of the sound of a ticking clock with intensity 10−9 watts per square inch? Use a logarithmic model to
In-s [12.5K]

Answer:

β = (-0.19 dB).

Step-by-step explanation:

The formula which is used to calculate the decibel level of a sound is given by :

\beta=10\log (\dfrac{I}{I_o})

I is intensity of the sound of a ticking clock

I_o=10^{-12}\ watts per square meter

Since, 1\ \text{inch}^2=\dfrac{1}{1550}\ \text{m}^2

The intensity of a monster truck is converted into per square meter as follows:  

10^{-9}\ {W/in^2}=   \dfrac{10^{-9}}{1550}\ W/m^2\\\\10^{-9}\ {W/in^2}=6.45\times 10^{-13}\ W/m^2

So, Decibal level is :

\beta=10\log (\dfrac{6.45\times 10^{-13}}{10^{-12}})\\\\\beta =-0.19\ dB

So, the decibel level of the sound of a ticking clock is (-0.19 dB).

7 0
2 years ago
Read 2 more answers
An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
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