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Scrat [10]
2 years ago
6

Colton has 8 comedy movies, 6 action movies, 5 fantasy movies, and 1 drama movie on his list of favorite movies.

Mathematics
2 answers:
Tema [17]2 years ago
5 0
For every 5 movies on his list, there are 2 comedy movies.
Luda [366]2 years ago
5 0

Answer:

For every 5 movies on the list there are 2 comedy movies.

Step-by-step explanation:

In this question Colton has comedy movies = 8

                                             Action movies = 6

                                             Fantasy movies = 5

                                            Drama movies = 1

So total number of movies in his favorite list = 8+6+5+1 = 20

Now we have to calculate the ratio of each kind of movie out of total number of movies.

The ratio of Comedy movie to the total =\frac{8}{20} =\frac{2}{5}

Ratio of Action movies to the total =\frac{6}{20} =\frac{3}{10}

Ratio of Fantasy movie to the total= \frac{5}{20} =\frac{1}{4}

and the ratio of drama to the total number of movies =\frac{1}{20}

After analyzing these solutions we can say that for every 5 movies on the list, there are 2 comedy movies.

                                               

                                       

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The sign is buried 0.60 of a meter below the ground.

Step-by-step explanation:

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2 years ago
Without using a calculator, what is 30% of 546? (You can round up to avoid decimal points)
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Answer:

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The Rockville Employment Agency just placed Howard Jacobson in a job as a junior pharmacist. The job pays $51.2k. The agency fee
yan [13]

His annual salary as a pharmacist is $51,200

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Howard must pay to  the employment agency to the nearest dollar = $1,182

6 0
2 years ago
A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-
sergiy2304 [10]

Answer:

The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

Step-by-step explanation:

The confidence interval formula for mean difference for a paired data is as follows:

CI=\bar x_{d}\pm t_{\alpha/2, (n-1)}\times \frac{s_{d}}{\sqrt{n}}

Here,

\bar x_{d} = sample mean of the difference,

s_{d} = sample standard deviation of the difference,

<em>n </em>= sample size (both samples are of same size).

t_{\alpha/2, (n-1)} = critical value of <em>t</em>

(<em>n</em> - 1) = degrees of freedom

The information provided is:

<em>n</em> = 5

Confidence level = 95%

The critical value of <em>t</em> is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (5-1)}

               =t_{0.025, 4}

               =2.776

*Use a <em>t</em>-table for the critical value of <em>t</em>.

Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

4 0
2 years ago
A baker determined the annual profit in dollars from selling pies using p n( ) = 52n − 0.05n2 , where n is the number of pies so
miss Akunina [59]

Answer:

<u>The annual profit if the baker sells 400 pies would be US$ 12,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Annual profit in dollars from selling pies using p n( ) = 52n − 0.05n² , where n is the number of pies sold

Annual sales of the baker = 400 pies

2. Let's solve p for 400 pies

p n( ) = 52n − 0.05n²

p (n₄₀₀) = 52 * 400 − 0.05 * 400²

p (n₄₀₀) = 20,800 − 0.05 * 160,000

p (n₄₀₀) = 20,800 − 8,000

p (n₄₀₀) = 12,800

<u>The annual profit if the baker sells 400 pies would be US$ 12,800</u>

Note: Same answer to question 14179960, answered by me today.

3 0
2 years ago
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