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Alona [7]
2 years ago
8

Answer question please

Mathematics
1 answer:
nataly862011 [7]2 years ago
4 0

∠EFH = 6y + 14

since HF bisects ∠GFI then ∠GFH = ∠HFI = 2y + 6

hence ∠EFH = ∠EFG + ∠GFH = 4y + 8 + 2y + 6 = 6y + 14


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Note necessary facts about isosceles triangle ABC:

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1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.

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BC=2CD.

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