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1 year ago

Answer question please

Mathematics

1 answer:

nataly862011 [7]1 year ago

4 0

∠EFH = 6y + 14

since HF bisects ∠GFI then ∠GFH = ∠HFI = 2y + 6

hence ∠EFH = ∠EFG + ∠GFH = 4y + 8 + 2y + 6 = 6y + 14

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