Question

3x+8+2ax≥3ax−4a what is x?

Answer 1

X≥
$- \frac {4 (2 + a)}{3 - a}$
solve the inequality by finding the roots and creating test intervals.

Answer 2

Answer:

$\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}$

Step-by-step explanation:

Given: the inequality 3x+8+2ax≥3ax−4a

To Find: value of x

Solution:

in given inequality

$3\text{x}+8+2\text{a}\text{x}\geq 3\text{a}\text{x}-4\text{a}$

$3\text{x}+2\text{a}\text{x}-3\text{a}\text{x}\geq -4\text{a}-8$

$\text{x}(3+2\text{a}-3\text{a})\geq -8-4\text{a}$

$\text{x}(3-\text{a})\geq -8-4\text{a}$

$\text{x}\geq \frac{-8-4\text{a}}{(3-\text{a})}$

$\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}$

therefore value of $\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}$