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2 years ago

In the process of glycolysis, what happens to glucose after it crosses the cell membrane into the cytoplasm of the cell?

2 answers:

8 0

Living organisms display the property of metabolism, which is a general term to describe the processes carried out to acquire and use energy. We know that people need to eat, and in our foods are various kinds of nutrients that our cells use. One large group of nutrients in our foods is carbohydrates, which supply our cells with glucose.

SSSSS [86.1K]2 years ago

7 0

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A farmer is being troubled by coyotes eating his sheep. in an attempt to solve the problem, he kills a sheep and laces its body

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The correct answer is "conditioned taste aversions".

Conditioned Taste Aversions is best described as an event wherein it occurs whilst an animal friends the flavor of a certain food with symptoms resulting from a poisonous, spoiled, or toxic substance. normally, taste aversion is developed after ingestion of food that reasons nausea, illness, or vomiting.

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2 years ago

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By interfering with fertilization

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2 years ago

26. Use arrows to connect the concept bubbles below, making a concept map. Be sure to label

Eddi Din [679]

Enter a compound inequality to show the levels that are within each range. Then graph the solutions.
Water is not a liquid if its temperature is above 100°C or below 0°C.
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2 years ago

The genome of a goldfish contains 96 chromosomes. how many chromosomes will each daughter cell have after mitosis of a goldfish

andreyandreev [35.5K]

The genome of a goldfish contains 96 chromosomes. how many chromosomes will each daughter cell have after mitosis of a goldfish cell is complete

C. 95

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2 years ago

A boy threw a small bundle toward his girlfriend on a balcony 10. meters above him. The bundle stopped rising in 1.5 seconds. Ho

Alisiya [41]

Hi!

We know that the boy must have thrown the bundle with some initial velocity 'v', and that the bundle stops after 1.5 seconds at a height 's' with a final velocity 'u' -which would be 0.

Our known values thus are:

Time (t) = 1.5 s

Final velocity (u) = 0 m/s

Gravitational acceleration (g) = -9.8 m/s^(2)

Note: that the acceleration is negative as it is opposing the direction of motion (acting down on the object, causing deceleration)

We will be using equations of motion for an accelerating object to solve first for initial velocity, in order to find the distance.

<h3>Initial Velocity using v = u + at</h3>

Rearranging the equation, and using the value 'g' as our acceleration, we get, u = v - at

u = 0 - (-9.8)(1.5) = 14.7m/s

<h3>Distance Travelled using v^2 = u^2 + 2as</h3>

Rearranging the equation, we get, s= v^(2) - u^(2) / 2a

s = 0^(2) - 14^(2) / 2(-9.8)

Note: the negative sign is not a part of the initial velocity, but a part of the equation

s = - 216.09 / -19.6 = 11.025 m

The distance traveled by the bundle is hence, ~ 11 meters, which is high enough for the girl to catch.

Hope this helps!

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2 years ago