Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
Answer:
The price would be decreased by 18 bozats
Step-by-step explanation:
The following information is given in the question
x = number of kilograms of snig sold
P = Price per kilogram
And, the equation is
p = 300 - 18x
Now if an extra kilogram is sold so it should be x+1
Now the new price is
New price = 300 - 18(x + 1)
= 300 - 18x - 18
Therefore the price would be decreased by 18 bozats
Remember that an extraneous solution of an equation is a solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation.
First, we are going to solve our equation algebraically:
Step 1 simplify the equation:
Step 2 subtract 5 from both sides of the equation:
Step 3 square both sides of the equation:
Next, we are going to replace our solution in our original equation and check if it is a valid solution:
Since 9 is not equal to 1, is not valid solution of the equation; therefor it is an extraneous solution.
We can conclude that the correct answer is: x = 16, solution is extraneous
Numerator is the the number above the line on a fraction, while the denominator is the number underneath the line.
is similar to
Fraction with numerator -6 and denominator 8
since the triangles are similar
angle DEC = 60 degrees
3 angles inside a triangle equal 180 degrees
BAC = DCE = 64
CBA = EDC = 56
DEC = 180 -56 -64 = 60 degrees
used angle-angle theorem
