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kirza4 [7]
2 years ago
7

Jane and your Andrea pick apples Andrew pics three times as many pounds as Maria Jane pics two times as many pounds as Andrew th

e total weight of app of the apples 840 pounds how many pounds of apples does Andre pick?
Mathematics
1 answer:
koban [17]2 years ago
3 0
Andrea picked 340 pounds
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Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.

Answer: A_{CGD}=41.

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2 years ago
Diego and Amit were trying to solve the equation: x^2-8x=1x 2 −8x=1x, squared, minus, 8, x, equals, 1 Diego said, "I can solve b
labwork [276]

Answer:

Both.

Step-by-step explanation:

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2 years ago
If all the components of a vector are equal to 1, then that vector is a unit vector. if all the components of a vector are equal
RideAnS [48]
The statement to this question is true this is true
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2 years ago
A dvd normally costs $15. It is reduced to $9.75 in a sale. How much is the percentage reduction
Ivahew [28]

Answer:

You are paying 65% of the original price.

Step-by-step explanation:

So what I did is trial and error by 5 so I started with 75% and then 70% and so on until 65%

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Kurtosis of a normal data distribution is a ___________________ Group of answer choices Measure of data centrality Measure of da
Irina18 [472]

Answer:

Option A, Measure of data centrality

Step-by-step explanation:

Normal distribution curve determines the skewness of the data as to what extent is is disoriented from the normal distribution curve. Also, it is the probability distribution curve that determines whether the data set is two legged, one legged or it lies under which probability curve.

Hence option A is correct

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