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liraira [26]
2 years ago
10

select from the drop-down menus to correctly complete each statement. |−4| equal to |4| . |−4| is the distance from −4 to on a n

umber line
Mathematics
2 answers:
Yuliya22 [10]2 years ago
8 0

Answer:

The appropriate missing umber for this statement is "0"

Step-by-step explanation:

ElenaW [278]2 years ago
3 0


We need to select appropriate missing words from the drop-down menus to correctly complete each statement.

First statement is

"|−4| equal to |4| ".

Answer:

We know that absolute value of -4 and 4 can be equal only when their magnitude is considered.

Hence appropriate missing word will be "magnitude".


Second statement is:

" |−4| is the distance from −4 to on a number line."

we know that absolute value represents distance from origin or you can say 0.

so the appropriate missing word is "0".

You might be interested in
The most economical proportion for a right circular cone is to have its height three times long as its base diameter. What later
defon

9514 1404 393

Answer:

  ∛(2500π)√37 m² ≈ 120.911 m²

Step-by-step explanation:

If the height is 3 times the diameter, it is 6 times the radius. Then the volume is ...

  V = 1/3πr²h

  V = 1/3πr²(6r) = 2πr³

For a volume of 100 m³, the radius is ...

  100 m³ = 2πr³

  r = ∛(50/π) m

The lateral area of the cone is computed from the slant height. For this cone, the slant height is found using the Pythagorean theorem:

  s² = r² +(6r)² = 37r²

  s = r√37

Then the lateral area is ...

  LA = πrs

  LA = π(∛(50/π) m)(∛(50/π) m)√37

  LA = ∛(2500π)√37 m² ≈ 120.911 m²

5 0
2 years ago
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
2 years ago
What’s the domain and range?<br><br> An airplane travels at 565 mph.
viktelen [127]

Answer:

<u>Domain:</u>

The domain of this can be any value between 0 to 565 miles per hour

<u>Range:</u>

The reasonable range can be the distance traveled which can be from 0 to 13,560 miles (no plane travel is longer than 24 hours, we assume).

Step-by-step explanation:

Domain is the input, set of x values for the function.

Range is the output, set of y values for the function.

This isn't a function essentially, but it is given that an Airplane travels at 565 miles per hour.

<em>We can say that the domain will be the speed of the airplane and the range would be the distance it travels.</em>

<em />

<u>Domain:</u>

The domain of this can be any value between 0 to 565 miles per hour

<u>Range:</u>

The reasonable range can be the distance traveled which can be from 0 to (565*24=13,560 miles) 13,560 miles (no plane travel is longer than 24 hours, we assume).

4 0
2 years ago
Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.
Lelu [443]
Let's put it this way:  If you plot a few non-x-intercept points and then draw a curvy line through them,you will not know if you got the x-intercepts even close to being correct. <span>The only way you can be sure of your x-intercepts is to set the quadratic equal to zero and solve. So its a matter of guessing from the pictures. Basicaly said, the calculator won't give you the exact result.</span>
4 0
2 years ago
Read 2 more answers
A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr
guajiro [1.7K]

Step 1

Find the Volume of the two balls

we know that

the Volume of a sphere is equal to

V=\frac{4}{3} \pi r^{3}

In this problem we have

r=1.5\ in

Substitute

V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}

so

the volume of the two balls is equal

V=2*4.5\pi=9 \pi\ in^{3}

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to    

V=\pi r^{2}h

In this problem we have

r=1.5\ in

h=4*r=4*1.5=6\ in    

Substitute

V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}    

Step 4

Find the volume of the square prism

The volume of the prism is equal to

V=Bh

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

B=(2*1.5)^{2}=9\ in^{2} -----> the base is equal to the diameter    

h=4*r=4*1.5=6\ in  

Substitute

V=9*6=54\ in^{3}

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}  

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is 14.14\ in^{3}

the amount of wasted space in the prism is  25.73\ in^{3}

Find the difference

25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}

The package that has the least amount of wasted space is the cylinder

therefore

<u>the answer is the option</u>

the cylinder because it has approximately 11.6 in.3 less wasted space than the prism

5 0
2 years ago
Read 2 more answers
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