Question

Pam's eye–level height is 256 feet above sea level and Adam's eye–level height is 400 feet above sea level. What expression shows how much farther Adam can see to the horizon?

Answer 1

Answer:

To solve this problem, we need to use the following formula

$d=\sqrt{\frac{3h}{2} }$

Where $h$ is the eye-level height and $d$ is the horizontal distance to the horizon.

For Pam, we know that $h=256ft$,

$d=\sqrt{\frac{3(256)}{2} }=\sqrt{384} \approx 19.6$

She can see around 19.6 feet to the horizon.

For Adam, we know that $h=400 ft$

$d=\sqrt{\frac{3(400)}{2} }=\sqrt{600} \approx 24.5$

He cansee around 24.5 feet to the horizon.

Now, the difference is

$\Delta d= d_{Adam} -d_{Pam} \\\Delta d= 24.5 - 19.6 = 4.9$

Therefore, Adam can see 4.9 feet much farther than Pam.

Additionally, the expression that models this situation is $\Delta d= d_{Adam} -d_{Pam}$

Answer 2

Answer:

B

Step-by-step explanation:

then

a=2 and b=6

ur welcome ;)