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djyliett [7]
2 years ago
3

what is the difference of the polynomials? (5x3 4x2) – (6x2 – 2x – 9) –x3 6x2 9 –x3 2x2 – 9 5x3 – 2x2 – 2x – 9 5x3 – 2x2 2x 9

Mathematics
2 answers:
hram777 [196]2 years ago
6 0

Answer:

5x^3 - 2x^2 +2x +9

Step-by-step explanation:

(5x^3+4x^2) – (6x^2 – 2x – 9)

To simplify the polynomials we need to subtract

WE have negative sign in between so we multiply the second parenthesis by -1

5x^3+4x^2 – 6x^2 +2x +9

Now we combine like terms

+4x^2 - 6x^2 = -2x^2

so the polynomial becomes

5x^3 - 2x^2 +2x +9

blondinia [14]2 years ago
5 0
If you would like to know the difference of the polynomials, you can do this using the following steps:

<span>(5x^3 + 4x^2) – (6x^2 – 2x – 9) – x^3 = 5x^3 + 4x^2 - 6x^2 + 2x + 9 - x^3 = 4x^3 - 2x^2 + 2x + 9

The correct result woul</span>d be <span>4x^3 - 2x^2 + 2x + 9.</span>
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The smallest number by which 28 should be multiplied so as to get a perfect square is​
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Answer:

7.

Step-by-step explanation:

28 = 2^2 * 7.

To multiply 28 to get a perfect square, we can multiply it by 7 to get 2^2 * 7^2, which is 14 squared.

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An orange is shot up into the air with a catapult. The function h given by h(t)=15+60t-16t^2 models the orange’s height, in feet
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Complete question is:An orange is shot up into the air with a catapult. The function h given by h(t) = 15 + 60t - 16t² models the orange’s height, in feet, t seconds after it was launched.

Select all the true statements about the situation.

Options:

1. The domain of function h only contains values greater than or equal to 0.

2. The orange is at the same height 1 second after launch and 2 seconds after launch.

3. After 3 seconds, the orange has hit the ground.

4. The orange is 15 feet above the ground when it is launched.

5. The value t = 10 does not belong to the domain of h.

Answer:

Option 1 - True

Option 2 - False

Option 3 - False

Option 4 - True

Option 5 - True

Step-by-step explanation:

Looking at the options,

-The domain is the x or t value and it is time. Now, time can only be positive or greater than or equal to zero i.e. t ≥ 0. Thus, option 1 is true.

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h = 15 + 60(1) - 16(1)²

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Also, at t = 2 seconds;

h = 15 + 60(2) - 16(2)²

h = 15 + 120 - 64 = 71 ft

So,value of h is not the same at t = 1 and t = 2. Thus, option 2 is not true.

- The orange will hit the ground when h(t) = 0.

However, at t = 3;

h(t) = 15 + 60(3) - 16(3)²

h(t) = 51 ft

h(t) is not equal to zero at t = 3, so option 3 is false

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h(0) = 15 + 60(0) - 16(0)²

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- At t=10, h(t) = 15 + 60(10) - 16(10)²

h(10) = -985

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2 years ago
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Step-by-step explanation:


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Answer:

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Step-by-step explanation:

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