Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
Answer: A y=4x -5 and y=4x+5
Step-by-step explanation:
They have no solutions because they have the same slopes but different y intercepts. That works with any equation.
Answer:1.3
Step-by-step explanation:
Case 1: If we multiply f(x) = |x| by a fraction greater than zero and less than 1, the width of the resulting graph will increase. If the vertex of the original function is moved 2 units to the right, then we'd replace |x| with |x-2| Only the coefficient (3/4) satisfies the "wider graph" requirement here.
Next time you list answr possibilities, please type them in only one per line, or separate them with commons, semicolons or the like.
Answer:
15 dollers or 22.5%
Step-by-step explanation:
thank you i hope this helps
