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2 years ago

The ground electron configuration of a tc atom is [kr]5s24d5. what is the electron configuration of a tc3+ ion?

Physics

2 answers:

Sidana [21]2 years ago

8 0

Answer

$[kr]4d^4$

Explanation

Given that the tc atom has electronic configuration $tc=[kr]5s^24d^5$ we find the electronic configuration of the ion as follows

Step 1

Because the 5s orbital is further away than the 4d from the nucleus , during the ionization process the two 5s electrons will be removed first. As as result the $tc^{2+}$ has electronic configuration $[kr]4d^5.$

Step 2

All that is left is to remove one more electron. This electron is removed from the 4d orbital. As a result, the $tc^{3+}$ ion has electronic configuration

$tc^{3+}=[kr]4d^4.$

grandymaker [24]2 years ago

5 0

Answer:

poopi stinki

Explanation:

hi its C btw

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You are designing a spacecraft intended to monitor a human expedition to Mars (mass 6.42×1023kg, radius 3.39×106m). This spacecr

ludmilkaskok [199]

Answer:

h = 17 10⁶ m from surface of mars

Explanation:

For this exercise we will use Newton's second law where force is the force of universal gravitation

F = m a

The acceleration is centripetal

a = v² / r

G m M / r² = m v² / r

The speed module is constant, so we use the uniform motion ratio

v = d / t

Where the distance is the length of the circumference and the time is the period of the orbit

d = 2π r

v = 2π r / T

We replace

G M / r² = (4π² r² / T) / r

r³ = G M T² / 4π²

Let's reduce time to SI units

T = 24.66 h (3600 s / 1 h) = 88776 s

Let's calculate

r = ∛ 6.67 10⁻¹¹ 6.42 10²³ 88776² / 4π²

r = ∛ 8.5485 10²¹ m

r = 2,045 10⁶ m

This is the distance from the center of the planet, The height, which is the distance from the surface is

r = $R_{m}$ + h

h = r - $R_{m}$

h = 20.45 10 6 - 3.39 106

h = 17 10⁶ m

3 0

3 years ago

The speed of a bus increases uniformly from 15 ms per second to 60 ms per second in 20 seconds. calculate 1. the average speed 2

joja [24]

Vf= 60m/s
vs = 15m/s
t=20s
a = vf-vs/t
a = 45m/s / 20s
a = 2,25 m/s²
S = vs *t + 1/2 a*t²
S = 15 m/s*20s +1/2 * 2,25m/s² * 400 s²
S = 300m + 450m
S = 750m
v average = 750m/20s
v average = 37,5 m/s

3 0

2 years ago

Read 2 more answers

You are standing at the midpoint between two speakers, a distance D away from each. The speakers are playing the exact same soun

Rzqust [24]

Answer:

Explanation:

wave length of sound waves = velocity / frequency

= 340 / 170

λ = 2 m.

When the position of man is exactly at the meddle point between the speakers , sound waves from the speakers reaching man are in same phases ( path difference is zero. ) so intensity of sound is maximum .

Now , the man starts moving towards one of the speakers , his distance from one speaker becomes closer than the other creating path difference for the sound waves reaching his ears.

If he walks a distance of .5 m towards one speaker , path difference created

= .5 x 2 = 1 m

So , path difference = λ /2 ,

there will be destructive interference so minimum sound will be heard there.

When he walks a distance of 1 m , path difference created = 2m

path difference = λ

so there is constructive interference and maximum sound will be heard there.

Again we he walks a distance of 1.5 m , path difference created = 3 m

path difference = 3 λ /2

So there will be destructive interference so minimum sound will be heard there.

In this way we see that man starts from a point of maximum sound intensity , reaches a point of minimum sound intensity , then reaches a point of maximum sound intensity . At last he reaches a position of minimum sound intensity.

3 0

2 years ago

Compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 10

DochEvi [55]

Answer:

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Explanation:

Let's start by calculating each force.

Gravitational force

F = $G \frac{m_1m_2}{r^2}$

let's calculate

F = 6.67 10⁻¹¹ 1 1 / 1²

F = 6.67 10⁻¹¹ N

Electric force

F = $k \frac{q_1q_2}{r^2}$

indicates that the charge is q = 10 C

F = 9 10⁹ 10 10 / 1²

F = 9 10¹¹ N

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

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2 years ago

(d) A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scat

irakobra [83]

QUESTION:-A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scattered from the paper and reflected from the mirror.
Describe how scattering by paper and reflection by a mirror are different from each other.

ANSWER: Scattering sends or reflects light from each point on the object in all directions, whereas reflection sends light from each point on the object in one direction only (or to one point)

5 0

2 years ago