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Darina [25.2K]
2 years ago
14

Using all three of Newton's laws of motion, carefully describe the motion of a baseball beginning when the ball is resting in th

e pitcher's glove as he stands on the mound until the ball is hit by the batter (assume the ball is hit). Ignore what kind of pitch is thrown and air resistance. The answer should focus on the forces and motion of the ball (not the players), and should include which of Newton's laws each motion/force follows. в у = = т т. O Words
Physics
1 answer:
Paha777 [63]2 years ago
3 0

Answer:

As the ball sits in the glove of the pitcher, it is acted upon by the downward force of gravity. Based on Newton’s 3rd law (N3), the ball pulls upward on the Earth with exactly the same force. The force of gravity is perfectly balanced by the upward normal force of the glove on the ball. There is no net force, so the ball remains at rest in the glove based on Newton’s 1st law (N1). When ready to pitch, the pitcher’s hand lifts the ball out of the glove. The ball is now being acted on by a net force from the pitcher’s hand and experiences motion, per Newton’s 2nd law (N2). The upward force of the pitcher’s hand on the ball is stronger than the downward pull of gravity, so the ball moves up, out of the glove, and behind the pitcher’s head. Its inertia is continually changing due to the net force (N1). During this movement, the ball is exerting a force on the pitcher’s hand equal and opposite to the force the hand exerts on the ball (N2). Because the ball’s mass is smaller, its acceleration is larger, resulting in a net movement of the ball. As the pitcher throws the ball forward, he exerts a large force on the ball, causing it to accelerate to a high speed (N2). The moment the ball is released, this external force stops once the ball reaches the same velocity as the pitcher’s hand. Now, the force of gravity is the only force acting on the ball. The force of gravity is unbalanced and in the downward direction, this causes the path of the ball to bend slightly downward as it travels towards the batter. The ball exerts a force on the Earth equal and opposite to the force of gravity (N3); again, due to the mass of the Earth, the effect on the Earth is negligible (N2). In the horizontal direction, there are no net forces, so the ball moves at the same speed and in the same direction as it did when it was released by the pitcher’s hand (N1). It continues until it reaches the plate, where the batter swings the bat and hits the ball. The bat exerts a net force on the ball, causing it to change both speed and direction (N1). On impact, the ball’s velocity is reduced to zero (this is a large deceleration) (N1 and N2). The force of the bat then causes the ball to accelerate and move in a new direction (N1 and N2). The ball exerts the same force on the bat (N3), which causes the bat to slow slightly as the batter finishes the swing.

Explanation:

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An airplane is delivering food to a small island. It flies 100 m above the ground at a speed of 150 m/s .
miss Akunina [59]

Answer:

The airplane should release the parcel 6.7*10^2 m before reaching the island

Explanation:

The height of the plane is y_0=100m, and its speed is v=150 m/s

When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is

y=y_0 - \frac{gt^2}{2}    [1]

And the distance X is

x = V.t     [2]

Being t the time elapsed since the release of the parcel

If we isolate t from the equation [1] and replace it in equation [2] we get

X = V . \sqrt{\frac{2y_0}{g}}

Using the given values:

x = 150 m/s  \sqrt{\frac{2\times 100m}{9.8 m/sec^2}}

x = 6.7*10^2 m

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2 years ago
A student librarian lifts a 2.2 kg book from the floor to a height of 1.25 m. He carries the book 8.0 m to the stacks and places
Montano1993 [528]
The solution to your problem is as follows:


2.2Kg*9.8m/s = 21.56N 
<span>
21.56N*1.25m = 26.95J </span>


<span>We're only concerned with the work done against gravity, lifting the books to 1.25 meters. the distance walked has no effect on the problem, unless you take into account the wind resistance and the force needed to overcome it. Also, lowering the books onto the shelf doesnt count, because gravity does the work on the books.</span>
5 0
2 years ago
Read 2 more answers
Calcular la resistencia de una varilla de grafito de 170 cm de longitud y 60 mm2. Resistividad grafito 3,5 10-5 Ωm
ozzi

Answer:

R = 0.992 Ω

Explanation:

En esta pregunta, dada la información que contiene, debemos calcular la resistencia de la varilla de grafito.

Matemáticamente,

Resistencia = (resistividad * longitud) / Área De la pregunta;

Resistividad = 3,5 * 10 ^ -5 Ωm

longitud = 170 cm = 1,7 m

Área = 60 mm ^ 2 = 60/1000000 = 6 * 10 ^ -5 m ^ 2

Conectando estos valores a la ecuación anterior, tenemos;

Resistencia = (3.5 * 10 ^ -5 * 1.7) / (6 * 10 ^ -5) =

(3.5 * 1.7) / 6 = 0.992 Ω

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2 years ago
A 23.5 kg object travels a distance of 85 m in 30 s. Find the momentum. (Hint: you must find speed first)
kherson [118]
Speed = 85/30 m/s
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A soccer player runs up behind a 0.450-kg soccer ball traveling at 3.20 m/s and kicks it in the same direction as it is moving,
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To develop this problem it is necessary to use the concepts related to Impulse.

The impulse is defined as the change in velocity at the rate of mass, that is

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m = Mass

\Delta V = Change in Velocity

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Therefore the magnitude of the impulse is 4.32 Kg.m/s

7 0
2 years ago
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