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satela [25.4K]
1 year ago
6

A physics student stands on the rim of the canyon and drops a rock. The student measures the time for it to reach the bottom to

be 3.2 seconds. How deep is the canyon?
Physics
1 answer:
madam [21]1 year ago
5 0

Answer:

Canyon is 50.176 meter deep.

Explanation:

The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.

Given data:

Time = t = 3.2 s

Initial velocity = v_{i} = 0 m/s

Gravitational acceleration = g = 9.8 m/s²

Height = h = ?

According to second equation of motion

h = v_{i}t + \frac{1}{2}gt^{2}

As initial velocity is zero, So the first term of right hand side of above equation equal to zero

h = \frac{1}{2}gt^{2}

h = (0.5)(9.8)(3.2)²

h = 50.176 m

This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.

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Answer:

Explanation:

Force of friction at car B ( break was applied by car B ) =μ mg = .65 x  2100 X 9.8  = 13377 N .

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( b )

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TEA [102]
Centripetal force <span>a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. It is calculated by the expression:

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F = 7.26(31.95)^2 / (1.215) = 6100 N</span>
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dimulka [17.4K]

Answer:

475

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Out of all given choices, activities and donor list can be found on the given kind of informative website.

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