Answer:
6.16 m/s
0.0105 m
Explanation:
Let the ground 0 for potential reference be at where the spring is compress 0.24 m. The the man would jump from a height h = 2.5 + 0.24 = 2.74 m from it. We can apply the law of energy conservation knowing that as the man jumps, his potential energy converts to kinetic energy, then finally to elastic energy:
where m = 80 kg is the man mass, g = 9.81 m/s2 is the gravitational acceleration, h = 2.74 m is the potential distance he travels, k N/m is the spring constant and x = 0.24 is the distance it compresses
Similarly at the position where it compresses by 0.12 m, it's 0.24 - 0.12 = 0.12 m far from ground 0.
When he steps gently, then his gravity force would equal to his spring force
Answer:
e. Not enough information to determine
Explanation:
This question is incomplete. Here is the complete question with my solution afterwards;
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.
What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)
a. The ladybug begins to slide
b. The gentleman bug begins to slide
c. Both bugs begin to slide at the same time
d. Nothing ever happens
e. Not enough information to determine
The centripetal force acting on a rotating body or bugs can be written as,
mass of the corresponding bugs
corresponding radial distance of each bug
angular speed of the turntable
The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable
∝
Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.
Option "e" is correct.
Answer:
The frequency is
Explanation:
From the question we are told that
The time taken for it to decay to half its original size is
Let the voltage of the capacitor when it is fully charged be
Then the voltage of the capacitor at time t is said to be
Now this voltage can be mathematical represented as
Where RC is the time constant
substituting values
Generally the cross-over frequency for a low pass filter is mathematically represented as
substituting values