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Rom4ik [11]
2 years ago
12

Lorenzo is making a prediction. “I learned that nonmetals increase in reactivity when moving from left to right. So I predict th

at xenon will be more reactive than iodine.” Is Lorenzo correct? If so, why? If not, explain his error.
Physics
2 answers:
nadezda [96]2 years ago
6 0
That prediction is not correct because Xenon is extremely stable; column 18 of the periodic table contains the noble gasses, which are stable because their outer-most energy levels are completely filled. Having the octet (8) of valence electrons means that the element no longer needs to lose or gain electrons to gain stability.

The column 17 elements are unstable because they only have one valence electron short of the stable octet configuration of the noble gasses.
son4ous [18]2 years ago
6 0
<span>Lorenzo is not correct. Nonmetals increase in reactivity from left to right because nonmetals on the right have more valence electrons. They need to gain fewer electrons to have a full outer shell. However, this trend only continues until group 17, because the noble gases already have a full outer shell. Therefore, their reactivity is the least of all the elements.</span>
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A coworker did not clean his work area before going home this could cause an accident so you quickly clean up the next day you s
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Answer:

THE FIRST ONE YOU SHOULD TELL HIM AND THE LAST ONE YOU SHOUDENT DO BECAUSE HE WILL DO IT AGAIN AND EXPECT OTHERS TO CLEAN UP AFTER HIM

Explanation:

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1 year ago
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Generalized global air circulation and precipitation patterns are caused by
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<span> Rising, warm, moist air masses cool and release precipitation as they rise and then at high altitude, cool
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1 year ago
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A long cylindrical rod of diameter 200 mm with thermal conductivity of 0.5 W/m⋅K experiences uniform volumetric heat generation
LuckyWell [14K]

Answer:

a, 71.8° C, 51° C

b, 191.8° C

Explanation:

Given that

D(i) = 200 mm

D(o) = 400 mm

q' = 24000 W/m³

k(r) = 0.5 W/m.K

k(s) = 4 W/m.K

k(h) = 25 W/m².K

The expression for heat generation is given by

q = πr²Lq'

q = π . 0.1² . L . 24000

q = 754L W/m

Thermal conduction resistance, R(cond) = 0.0276/L

Thermal conduction resistance, R(conv) = 0.0318/L

Using energy balance equation,

Energy going in = Energy coming out

Which is = q, which is 754L

From the attachment, we deduce that the temperature between the rod and the sleeve is 71.8° C

At the same time, we find out that the temperature on the outer surface is 51° C

Also, from the second attachment, the temperature at the center of the rod was calculated to be, 191.8° C

6 0
1 year ago
A basketball rolls off a deck that is 3.2 m from the pavement. The basketball lands 0.75 m from the edge of the deck. How fast w
Aneli [31]
The table is almost perfect. BUT ... since she called ay negative, that means she's calling the upward direction positive-y and the downward direction negative-y. In that case, since the ball moves downward from the deck to the pavement, the change in y should be negative 3.2 m. Everything else in her table is fine. Choice-D is the good one.

Now, regarding the speed of the ball ...
How long does it take to fall 3.2 m ?
Use the formula. D = 1/2 g T^2 .

3.2 = 4.9 T^2.

T^2 = 3.2/4.9

T = √(3.2/4.9) = 0.808 second.

The ball hit the pavement 0.808 second after it rolled off the deck. So that's also the time it took to move the 0.75 m horizontally.

Speed = distance / time

Speed = 0.75 m / 0.808 second

Speed = 0.928 meter/second .
6 0
2 years ago
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Can pockets of vacuum persist in an ideal gas? Assume that a room is filled with air at 20∘C and that somehow a small spherical
Ilya [14]

Answer:

time taken is 20 μs

Explanation:

given data

temperature = 20°C  = 293 K

radius = 1 cm

atomic mass of air = 29 u

to find out

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solution

we find here rms velocity of air particle that is

\frac{1}{2}mv^2 = \frac{3}{2}RT

here m is mass and t is temperature and v is speed and R is ideal gas constant i.e. 8.3145 (kg·m²/s²)/K·mol

v = \sqrt{\frac{3RT}{M} }  ............................1

v = \sqrt{\frac{3(8.314)293}{29*10{-3}kg} }

v = 501.99 m/s

so now for cover 1 cm

time taken by air

time take = \frac{r}{v}

time taken = \frac{1*10^{-2}m}{501.99}

time taken = 19.92 × 10^{6} s = 20μs

so time taken is 20 μs

3 0
2 years ago
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