Answer:
The gravitational potential energy equals the work needed to lift the object.
Explanation:
here we know that

work done is given as

Potential energy is given as

force due to gravity is given as

now here if we plug in the value of distance and force in the formula of work done then we will have

so here we got

so we can concluded that
The gravitational potential energy equals the work needed to lift the object.
Answer:
A 93%
Explanation:
= Pressure will be equal at inlet and outlet
= Density of water = 1000 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
= Velocity at inlet = 1.2 m/s
= Velocity at outlet
= Radius of inlet = 
= Radius of outlet
From Bernoulli's relation

From continuity equation

The fraction would be

The fraction is 93.0304%
<span>Let m1=10kg and m2=5kg and for our calculations assume right is positive and up is positive (note: for block hanging, the x axis is vertical so tilt your head to help)
For m1
Sigma Fx = ma
T - m1gsin35 = m1a where T = tension
For m2
m2g - T = m2a
Add equation together
m1a + m2a = T-m1gsin35 + m2g - T
a(m1 + m2) = m2g - m1gsin35
a= (5*9.8 - 10*9.8*sin35)/(10 + 5)
a= -0.48m/s/s
So the system is moving in the opposite direction of our set coordinate system where we said right positive, its negative so its moving left therefore down the ramp</span>
Answer:
Option B and C are True
Note: The attachment below shows the force diagram
Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂;
w = T₁/cos 60° -----(1)
w = T₂/cos 30° ----(2)
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°
T₁ cos 30° = T₂ cos 60°
T₂/T₁ = cos 30°/cos 60°
T₂/T₁ =1.73
Therefore, option a is false since T₂ > T₁
Option B is true since T₁ cos 30° = T₂ cos 60°
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
acceleration of rocket is given here as

now we know that

now integrating both sides



here since its given that rocket will accelerate for t = 10 s
so here we have


so after t = 10 s the speed of rocket will be 130 m/s upwards