Answer:
W ≈ 5.9 × 
J
Hence, option (c) is correct.
Given:
mass of box = 6 kg
Displacement of box = 10 m
To find:
Work done by the force = ?
Formula used:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
Solution:
Work done is equal to change is potential energy,
W = m g h
Where, W = Work done
m = mass of the box
h = displacement by the force
W = 6 × 9.8 ×10
W = 588 Joule
Thus, W ≈ 5.9 × J
Hence, option (c) is correct.
Answer:
b= 2.14 m
Explanation:
Given that
Weight of the board ,wt = 40 N
Wight of the first children , wt₁=500 N
Weight of the second children ,wt₂ = 350 N
The distance of the 500 N child from center ,a= 1.5 m
lets take distance of the 350 N child from center = b m
Now by taking the moment about the center of the board
We know that moment = Force x Perpendicular distance from the force
wt₁ x a = wt₂ x b
500 x 1.5 = 350 x b
b= 2.14 m
Therefore the distance of the 350 N weight child from the center is 2.14 m.
The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.
Answer:
maximumforce is F = mg
Explanation:
For this case we must use Newton's second law,
Σ F = m a
bold indicate vectors, so we will write it in its components x and y
X axis
Fₓ = maₓ
Axis y
Fy - W = m a
Now let's examine our case, with indicate that the bird is level, the force of the wings can have a measured angle with respect to the x axis, where the vertical component is responsible for the lift, let's use trigonometry to find the components
Cos θ = Fₓ / F
Fₓ = F cos θ
sin θ = Fy / F
Fy = F sin θ
Let's replace and calculate
F sin θ -w = m a
As the bird indicates that leveling at the same height, so the vertical acceleration is zero (ay = 0)
F sin θ = w = mg
The maximum value of this equation occurs when the sin=1, in this case
F = mg
We are given
the torque requirement of 97 Newton meter.
The formula of the torque is
τ = r * F * sinθ
where
τ is the torque
r = radius from the axis of rotation to the point of application.
F = force exerted
θ = the angle between the lever arm and the radius
Try to substitute the given and solve for F.
