Answer:
-6.6 km/h
Explanation:
In 7hr plane travelled 2020km;
For the first 4hr the average speed was 310km/h;
d=st, s=d/t;
Distance covered in first 4h is d = 310km/h×4h = 1240km;
See the image attached for further solution
Answer: 2.86 m
Explanation:
To solve this question, we will use the law of conservation of kinetic and potential energy, which is given by the equation,
ΔPE(i) + ΔKE(i) = ΔPE(f) + ΔKE(f)
In this question, it is safe to say there is no kinetic energy in the initial state, and neither is there potential energy in the end, so we have
mgh + 0 = 0 + KE(f)
To calculate the final kinetic energy, we must consider the energy contributed by the Inertia, so that we then have
mgh = 1/2mv² + 1/2Iw²
To get the inertia of the bodies, we use the formula
I = [m(R1² + R2²) / 2]
I = [2(0.2² + 0.1²) / 2]
I = 0.04 + 0.01
I = 0.05 kgm²
Also, the angular velocity is given by
w = v / R2
w = 4 / (1/5)
w = 20 rad/s
If we then substitute these values in the equation we have,
0.5 * 9.8 * h = (1/2 * 0.5 * 4²) + (1/2 * 0.05 * 20²)
4.9h = 4 + 10
4.9h = 14
h = 14 / 4.9
h = 2.86 m
Answer:
A. 261.6 hz.
B. 0.656 m.
Explanation:
A.
When yhe tube is open at one end and closed at the other,
F1 = V/4*L
Where,
F1 = fundamental frequency
V = velocity
L = length of the tube
When the tube is open at both ends,
F'1 = V/2*L
Where
F'1 = the new fundamental frequency
Therefore,
V/2*L x V/4*L
F'1 = 2 * F1
= 2 * 130.8
= 261.6 hz.
B.
F1 = V/4*L
Or
F'1 = V/2*L
Given:
V = 343 m/s
F1 = 130.8
L = 343/(4 * 130.8)
= 0.656 m.
Answer:
When touching the bar magnet ,the nail gets attached to the magnet from its metallic field is used to connect when taylor touched the nail to the bar magnet,the magnetic fields were ranged,and made a temporary magnet.
Explanation:
