A leopard of mass 65 kg climbs 7 m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g = 10 N/k
1 answer:
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Answer:
No, the apple will reach 4.20041 m below the tree house.
Explanation:
t = Time taken
u = Initial velocity = 2.8 m/s
v = Final velocity = 0
s = Displacement
g = Acceleration due to gravity = -9.81 m/s² = a (negative as it is going up)
Equation of motion
The height to which the apple above the point of release will reach is 0.39959 m
From the ground the distance will be 1.3+0.39959 = 1.69959 m
Distance from the tree house = 5.9-1.69959 = 4.20041 m
No, the apple will reach 4.20041 m below the tree house.
The values in the option do not reflect the answer.
Answer:
Explanation:
The strength of an electric field E produced by a single charge Q at a distance d from it is given by the formula: , where K represents the Coulomb constant.
Since the electric field E is derived from the Coulomb Force per unit charge using a positive test charge, the field's units will be in units of Newtons/Coulomb, and be the formula for the Coulomb electric force between to charges (Q1 and Q2),
but modified with only one charge showing in the numerator of the expression.
Answer:
Explanation:
This is a displacement vector since it is defined in terms of distance (meters, to be exact). The way you find the y-component is
which says that you multiply the magnitude of the vector (its length) by the sin of the direction (the angle):
and get
12.1 m