A car travels straight for 20 miles on a road that is 30° north of east. What is the east component of the car’s displacement to
the nearest tenth of a mile?
A.) -17.3 miles
B.) -10.0 miles
C.) 10.0 miles
D.) 17.3 miles
A.) -17.3 miles
B.) -10.0 miles
C.) 10.0 miles
D.) 17.3 miles
2 answers:
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Answer:
You will hear the note E₆
Explanation:
We know that:
Your speed = 88m/s
Original frequency = 1,046 Hz
Sound speed = 340 m/s
The Doppler effect says that:
Where:
f = original frequency
f' = new frequency
v = velocity of the sound wave
v0 = your velocity
vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.
Replacing the values that we know in the equation we have:
This frequency is close to the note E₆ (1,318.5 Hz)
Answer:
The wire meet the ground at an angle of 56.4 degrees
Explanation:
It is given that,
To support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground.
The hypotenuse is, H = 12 foot
The perpendicular distance is, P = 10 feet
The angle between the tree and the ground is 90 degrees
Using Pythagoras theorem as :
So, the wire meet the ground at an angle of 56.4 degrees. Hence, the correct option is (d).
The question is missing, but I guess the problem is asking for the distance between the cliff and the source of the sound.
First of all, we need to calculate the speed of sound at temperature of
:
The sound wave travels from the original point to the cliff and then back again to the original point in a total time of t=4.60 s. If we call L the distance between the source of the sound wave and the cliff, we can write (since the wave moves by uniform motion):
where v is the speed of the wave, 2L is the total distance covered by the wave and t is the time. Re-arranging the formula, we can calculate L, the distance between the source of the sound and the cliff:
First of all, we need to calculate the speed of sound at temperature of
The sound wave travels from the original point to the cliff and then back again to the original point in a total time of t=4.60 s. If we call L the distance between the source of the sound wave and the cliff, we can write (since the wave moves by uniform motion):
where v is the speed of the wave, 2L is the total distance covered by the wave and t is the time. Re-arranging the formula, we can calculate L, the distance between the source of the sound and the cliff: