A car travels straight for 20 miles on a road that is 30° north of east. What is the east component of the car’s displacement to
the nearest tenth of a mile?
A.) -17.3 miles
B.) -10.0 miles
C.) 10.0 miles
D.) 17.3 miles
A.) -17.3 miles
B.) -10.0 miles
C.) 10.0 miles
D.) 17.3 miles
2 answers:
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Answer:
The classification of that same issue in question is characterized below.
Explanation:
The given values are:
Current, I = 50.0 A
Diameter, d = 0.10 cm
(a)...
As we know,
⇒ Magnetic force = Copper wire's weight
So,
⇒
On putting the estimated values, we get
⇒
⇒
⇒
(b)...
As we know,
⇒
⇒
⇒
⇒
Answer:
Explanation:
Position of charge q₁ is (0,0)
Position of charge q₂ is (x₁,0)
So, the electric potential energy between the charges is given by :
Now the position of charge q₂ has been changes from (x₁,0) to (x₂,y₂). Now, electric potential energy between the charges is :
We know form the work energy theorem that, the change in potential energy is equal to the work done. Mathematically, it is given by :
Hence, the work done by the electrostatic force on the moving point charge is . Hence, this is the required solution.