64) Compare skeletal, smooth, and cardiac muscles as to their body location, microscopic anatomy, regulation of contraction, spe
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The speed is 0.956 m / s.
<u>Explanation</u>:
The kinetic energy is equal to the product of half of an object's mass, and the square of the velocity.
K.E = 1/2 m
where K.E represents the kinetic energy,
m represents the mass,
v represents the velocity.
K.E = 1/2 m
1.10 10^42 = 1/2
3.26
10^31
= (1.10
10^42
2) / (3.26
10^31)
v = 0.956 m / s.
Answer:
a) 19536 joules of work are done.
b) The work is done by the engine on the structure of the cart.
c) There are three options: (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.
d) 24442 joules of work are done.
e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.
f) The bigger engine uses more gas to go 22 meters.
g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.
Explanation:
a) If force applied in the cart is uniform, that is, constant in magnitude and direction and is parallel to distance travelled by the car, the work done on the cart is defined by the following equation:
(1)
Where:
- Force applied by the cart, measured in newtons.
- Distance travelled by the car, measured in meters.
- Work done on the cart, measured in joules.
If we know that and
, then the work done on the cart is:
19536 joules of work are done.
b) The work is done by the engine on the structure of the cart.
c) There are three options: (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.
d) If we know that and
, then the work on the cart is:
24442 joules of work are done.
e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.
f) The gas consumption is directly proportional to the square of velocity and mass of the cart and, hence, to the work done on the cart. In consequence, we conclude that the bigger engine uses more gas to go 22 meters.
g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.
Answer:
The change in gravitational potential energy is 45 J.
Explanation:
Given that,
Mass = 3 kg
Distance = 1.5 m
Gravitational field strength = 10 N/kg
We need to calculate the change in gravitational potential energy
Using formula of gravitational potential energy
Put the value into the formula
Hence, The change in gravitational potential energy is 45 J.
(a) 134.4 J
The total mechanical energy of the ball at the moment of launch is just equal to its initial kinetic energy:
where
m = 0.05 kg is the mass of the ball
u = 78.2 m/s is the initial speed
Substituting,
At the pinnacle of its trajectory, the total mechanical energy is sum of kinetic energy and potential energy:
where
is the acceleration of gravity
h = 37.8 m is the maximum height
Since the total energy must be conserved,
E = 152.9 J
Therefore, we can solve to find the kinetic energy of the ball at the pinnacle:
b) 74.2 m/s
When the ball is 5.60 m below the pinnacle point, the heigth of the ball is
So its potential energy is
The total energy is again the sum of potential and kinetic energy:
E = K + U
So the kinetic energy at that point is
And since the kinetic energy is
We can find the speed: