A 2.0 kg block on a horizontal frictionless surface is attached to a spring whose force constant is 590 N/m. The block is pulled
1 answer:
Answer:
The value is
Explanation:
From the question we are told that
The mass of the block is
The force constant of the spring is
The amplitude is
The time consider is
Generally the angular velocity of this block is mathematically represented as
=>
=>
Given that the block undergoes simple harmonic motion the velocity is mathematically represented as
=>
=>
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Answer:
A) i) E =α/ [2πrL(εo)]
ii) E=0
iii) E = α/(πrεo)
The graph between E and r for the 3 cases is attached to this answer ;
B) i) charge on the inner surface per unit length = - α
ii) charge per unit length on the outer surface = 2α
Explanation:
A) i) For r < a, the charge is in the cavity and takes a shape of the cylinder. Thus, applying gauss law;
EA = Q(cavity) / εo
Now, Qcavity = αL
So, E(2πrL) = αL/εo
Making E the subject of the formula, we have;
E =α/ [2πrL(εo)]
ii) For a < r < b; since the distance will be in the bulk of the conductor, therefore, inside the conductor, the electric field will be zero.
So, E=0
iii) For r > b; the total enclosed charge in the system is the difference between the net charge and the charge in the inner surface of the cylinder.
Thus, Qencl = Qnet - Qinner
Qinner will be the negative of Qnet because it should be in the opposite charge of the cavity in order for the electric field to be zero. Thus;
Qencl = αL - (-αL) = 2αL
Thus, applying gauss law;
EA = Qencl / εo
Thus, E = Qencl / Aεo
E = 2αL/Aεo
Since A = 2πrL,
E = 2αL/2πrLεo = α/(πrεo)
B) i) The charge on the cavity wall must be the opposite of the point charge. Therefore, the charge per unit length in the inner surface of the tube will be - α
ii)Net charge per length for tube is +α and there is a charge of - α on the inner surface. Thus charge per unit length on the outer surface will be = +α - (- α) = 2α
Explanation:
The given data is as follows.
Mass of small bucket (m) = 4 kg
Mass of big bucket (M) = 12 kg
Initial velocity () = 0 m/s
Final velocity () = ?
Height = 2 m
and, = 0 m
Now, according to the law of conservation of energy
starting conditions = final conditions
235.44 = + 78.48
= 4.43 m/s
Thus, we can conclude that the speed with which this bucket strikes the floor is 4.43 m/s.
Answer:
(2) −1 e
Explanation:
A quark is the lightest elementary particles which form hadron such as proton and neutron. A quark has fractional charge.
Up, charm and top quarks have charge where as down, strange and bottom quarks have
charge.
The antiparticle of up quark is antiup quark and has charge charge.
The antiparticle of down quark is antidown quark and has charge charge.
An antibaryon is composed of two anti-up quark and one anti-down quark.
Net charge of the anti-baryon is:
Thus, antibaryon has -1e charge.