At a given instant of time, a car and a truck are traveling side by side in adjacent lanes of a highway. The car has a greater v
1 answer:
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Answer:
Maximum emf = 5.32 V
Explanation:
Given that,
Number of turns, N = 10
Radius of loop, r = 3 cm = 0.03 m
It made 60 revolutions per second
Magnetic field, B = 0.5 T
We need to find maximum emf generated in the loop. It is based on the concept of Faraday's law. The induced emf is given by :
For maximum emf,
So,
So, the maximum emf generated in the loop is 5.32 V.
Answer:
A. 0.432
B. -1.92
C. 1.44 units/second
D. -3.2 units/second
Explanation:
A. To calculate her x position, we just use the following equation of motion to find the distance traveled:
here s = displacement
t = time (in seconds)
a = acceleration
Solving for the distance, we get:
s = 0.432 m
Since 0.432 meters east is equals to 0.432 meter in the positive x-direction, the x position is also 0.432.
B. Since the skater has a constant v - velocity of -3.2 m/s, (south means negative y axis), the total distance traveled is:
Distance = speed * time = -3.2 * 0.6 = -1.92 m
The answer is -1.92 units in the y-axis.
C. The x velocity component is the final speed in the east direction, which is going to be:
v = 1.44 units/second (in positive x direction)
D. Her y velocity component does not change, since the velocity towards the south is a constant 3.2 m/s
Thus the answer is -3.2 units/second in the y-axis.