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jekas [21]
2 years ago
13

a 2 meter tall astronaut standing on mars drops her glasses from her nose. how long will the astronaut have before he hits the g

round?
Physics
1 answer:
lorasvet [3.4K]2 years ago
7 0
Here,
Height (S) = 2m
Gravity on mars (g) = 3.7m/s^2
Initial velocity (u) = 0 m/s^2
By the one of the formula of the motion,
S = ut + 1/2at^2
2 = 0 * t + 1/2*3.7*t^2
2 = 1.85t^2
t^2 = 2/1.85 = 1.081
t =1.03s
So, it will take 1.03s long..

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Select the correct text in the passage. This paragraph attempts to explain the rain shadow effect, but it gets some of the facts
valentina_108 [34]

the sentence with leeward side and the sentence that has windward side both have errors.

5 0
2 years ago
Read 2 more answers
A standard 1 kilogram weight is a cylinder 51.0 mm in height and 42.0 mm in diameter. Determine the density of the material
worty [1.4K]

Answer:

14160 kg/m^3

Explanation:

First of all, we need to find the volume of the cylinder.

The volume of the cylinder is given by:

V=\pi r^2 h

where:

r=\frac{d}{2}=\frac{42.0 mm}{2}=21.0 mm=0.021 m is the radius

h=51.0 mm=0.051 m is the height

Substituting, we find

V=\pi (0.021 m)^2 (0.051 m)=7.1 \cdot 10^{-5} m^3

And the density is given by

d=\frac{m}{V}

where m = 1 kg is the mass. Substituting, we find

d=\frac{1 kg}{7.1\cdot 10^{-5} m^3}=14,160 kg/m^3

3 0
2 years ago
A nonlinear spring is used to launch a toy car. The car is pushed against the spring, compressing the spring 2.5 cm. The force t
dybincka [34]

Answer:

1.56 J

Explanation:

given,

Spring compression, x = 2.5 cm

Force exerts by the spring,

F = - k x

k = 5000 N/m

Potential energy stored = ?

energy stored in the spring

PE = \dfrac{1}{2}kx^2

PE = \dfrac{1}{2}\times 5000\times 0.025^2

PE = 1.56 J

Hence, the potential energy stored in the car is equal to 1.56 J.

5 0
2 years ago
g A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0
Margarita [4]

Answer:

Explanation:

If a particle move with time and expressed according to the formula:

f(t) = 0.01t⁴ − 0.03t³

a) Velocity is the change in motion of the particle with respect to time and it is expressed as;

v(t) =\frac{d(f(t))}{dt}

v(t) = 4(0.01)t^{4-1} - 3(0.03)t^{3-1}\\v(t) = 0.04t^3 - 0.09t^2

Hence the velocity of the particle at time t is v(t) = 0.04t^3 - 0.09t^2

b) To calculate the velocity after 1 second, we will substitute t = 1 into the function v(t) in (a) as shown:

v(t) = 0.04t^3 - 0.09t^2\\v(1) = 0.04(1)^3 - 0.09(1)^2\\v(t) = 0.04 - 0.09\\v(t) = -0.05

Hence the velocity after 1second is -0.05

c) The particle is at rest when when the time is zero.

Initially, the body is not moving and the time during this time is 0. Hence the particle is at rest when t = 0second

6 0
1 year ago
Nerve impulses are carried along axons, the elongated fibers that transmit neural signals. We can model an axon as a tube with a
Deffense [45]

Answer:

Explanation:

For resistance , the formula is

R = ρ l / S where ρ is resistivity , l is length and A is cross sectional area .

= .5 x 2 x 10⁻³ / 3.14 x (5 x 10⁻⁶)²

= .0127 x 10⁹

12.7 x 10⁶

12.7 MΩ

3 0
2 years ago
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