Ask question

Ask question

All categories

2 years ago

5

the distance between the sun and earth is about 1.5X10^11 m. express this distance with an SI prefix and kilometers

1 answer:

Angelina_Jolie [31]2 years ago

5 0

First, we write the SI prefixed. The SI unit for distance is meters.

Kilo = 10³
Mega = 10⁶
Giga = 10⁹
Terra = 10¹²

Because our value has ten to the power of 11, we will use the closest and lowest power prefix, which is giga.

1.5 x 10¹¹ / 10⁹
= 1.5 x 10² Gm or 150 Gm

Writing in kilometers, we simply repeat the procedure except we divide by 10³ this time.

1.5 x 10¹¹ / 10³
= 1.5 x 10⁸ km

You might be interested in

A force f = bx 3 acts in the x direction, where the value of b is 3.7 n/m3. how much work is done by this force in moving an obj

Elodia [21]

The answer would be 21.6 but rounded up it would be 22J.

8 0

2 years ago

A uniform sphere with mass M and radius R is rotating with angular speed ω1 about a frictionless axle along a diameter of the sp

liq [111]

Answer:

$W_2=\sqrt{\frac{3}{5} }W_1$

Explanation:

For the first ball, the moment of inertia and the kinetic energy is:

$I_1 =\frac{2}{5}MR^2$

$K_1 = \frac{1}{2}IW_1^2$

So, replacing, we get that:

$K_1 = \frac{1}{2}(\frac{2}{5}MR^2)W_1^2$

At the same way, the moment of inertia and kinetic energy for second ball is:

$I_2 =\frac{2}{3}MR^2$

$K_2 = \frac{1}{2}IW_2^2$

So:

$K_2 = \frac{1}{2}(\frac{2}{3}MR^2)W_2^2$

Then, $K_2$ is equal to $K_1$ , so:

$K_2 = K_1$

$\frac{1}{2}(\frac{2}{3}MR^2)W_2^2 = \frac{1}{2}(\frac{2}{5}MR^2)W_1^2$

$\frac{1}{3}MR^2W_2^2 = \frac{1}{5}MR^2W_1^2$

$\frac{1}{3}W_2^2 = \frac{1}{5}W_1^2$

Finally, solving for $W_2$ , we get:

$W_2=\sqrt{\frac{3}{5} }W_1$

5 0

2 years ago

Two vectors A and B are directed such that there is an angle θ between them. show answer Incorrect Answer Which of the following

Troyanec [42]

Answer:

Scalar product is between ║A║ ║ B║ and -║A║ ║ B║

Explanation:

Dot product between vec A and vec B is

A.B = ║A║ ║ B║ cos θ

Here, both ║A║ and ║B║ are positive and value of cos θ depends upon θ and lies between 1 and -1

So, Scalar product is between ║A║ ║ B║ and -║A║ ║ B║

8 0

2 years ago

A wheel completes 5.6 revolutions in 8 seconds.

nevsk [136]

Answer:

$86.15\pi rad/min$

Explanation: Angular velocity is the number of revolutions made per unit time.

We convert the number of revolutions to radians and the time given in seconds to minutes,

Given;

$1rev=2\pi rad\\therefore\\5.6rev=5.6*2\pi rad\\= 11.2\pi rad$

Also,

60s = 1 min

hence

$8s=\frac{8}{60}min\\=0.13min$

We now divide the number of revolution in radians by the time in minutes.

$\omega =\frac{11.2\pi}{0.13min}\\\omega=86.15\pi rad/min$

5 0

2 years ago

Read 2 more answers

How can light energy solve our real life problem?

kifflom [539]

Answer:

It gives our light which we need for probably everything.

Explanation:

4 0

2 years ago

Read 2 more answers