5,10,15,20,25,30, that's how much it should have been
Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m
Density=mass/volume
5.45g/ml=65g/V
V=65g/5.42g/ml
V=11.92ml
2NO2 means that there is 2 oxygen atoms and one nitrogen with two sets of that. So its the third one
Answer:
a). same as
b). less than
Explanation:
a). When a bicycle is moving, the linear speed at the top of the rear wheel is same as the linear speed at the top of the front wheel. Since the clown's bicycle is a rigid body, both the wheels that is the front wheel and the rear wheel will move with the same linear speed.
b). Since we know that angular speed varies inversely to the radius of the wheel.
That is ω = 1 / r
Since the rear wheel has twice the radius of that of the front wheel, therefore real wheel will have less angular speed than the front wheel.
Therefore, the angular speed of the rear wheel is less than the angular speed of the front wheel.
