The grooved pulley of mass m is acted on by a constant force F through a cable which is wrapped securely around the exterior of
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For a simple harmonic motion, the position of the mass at any time t is given by
where
A is the amplitude of the motion (in this problem, A=17.5 cm)
is the angular frequency of the oscillator
t is the time
The angular frequency of the motion in the problem is given by
And so, we can find the position x of the mass (with respect to the equilibrium position) at time t=2.50 s:
where
A is the amplitude of the motion (in this problem, A=17.5 cm)
t is the time
The angular frequency of the motion in the problem is given by
And so, we can find the position x of the mass (with respect to the equilibrium position) at time t=2.50 s:
Explanation:
The given data is as follows.
Mass of small bucket (m) = 4 kg
Mass of big bucket (M) = 12 kg
Initial velocity () = 0 m/s
Final velocity () = ?
Height = 2 m
and, = 0 m
Now, according to the law of conservation of energy
starting conditions = final conditions
235.44 = + 78.48
= 4.43 m/s
Thus, we can conclude that the speed with which this bucket strikes the floor is 4.43 m/s.