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Viefleur [7K]
2 years ago
13

The grooved pulley of mass m is acted on by a constant force F through a cable which is wrapped securely around the exterior of

the pulley. The pulley supports a cylinder of mass M which is attached to the end of a cable which is wrapped securely around an inner hub. If the system is stationary when the force F is first applied, determine the upward velocity v of the supported mass after 4 seconds. Use the values m = 30 kg, M = 11 kg, ro = 345 mm, ri = 230 mm, kO = 250 mm, and F = 85 N. Assume no mechanical interference for the indicated time frame and neglect friction in the bearing at O. What is the time-averaged value of the force T in the cable which supports the 11-kg mass?
Physics
1 answer:
Sidana [21]2 years ago
3 0

Answer:

Answer; v= 1.2654m/s

T= 110.76N

Explanation:

Apply Momentum Principle

Fdtro - Mgridt = Iow +Mvr

Fdtro - Mgridt = mK2 v/r1 + Mvr1

85 x 3x 0.345 -11 x 9.81 x 0.23 x 3 =30 x 0.25 x 0.25 x v/0.23 + 11 x v x 0.23 =

v = 1.2654m/s

To find the timed average value

Tdt -Mgdt =MV

T x 3 - 11 x 9.81 x 3 = 11 x 0.778

T= 110.76N

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Choose the correct statement of Kirchhoff's voltage law.
frutty [35]

Answer:

A) If one travels around a closed path adding the voltages for which one enters the negative reference and subtracting the voltages for which one enters the positive reference, the total is zero.

Explanation:

Kirchhoff's voltage law deals with the conservation of energy when the current flows in a closed-loop path.

It states that the algebraic sum of the voltages around any closed loop in a circuit is always zero.

In other words, the algebraic sum of all the potential differences through a loop must be equal to zero.

3 0
1 year ago
A body A of mass 1.5kg, travelling along the positive x-axis with speed 4.5m/s, collides with another body B of mass 3.2kg which
Pie
Momentum before the collision
x-direction:
p = m₁v₁ = 1.5 * 4.5 = 6.75
x-direction:
p = 0

momentum after the collision is conserved:
x-direction:
p = 6.75 = m₁v₁ + m₂v₂ = 1.5 * 2. 1* cos -30° + 3.2 * v₂*cos θ
y-direction:
p = 0 = m₁v₁ + m₂v₂ = 1.5 * 2.1 * sin -30° + 3.2 * v₂ * sin θ

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5 0
1 year ago
When 30 V is applied across a resistor it generates 600 W of heat: what is the magnitude of its resistance?
grandymaker [24]

Answer:

<h2>1.5 ohms</h2>

Explanation:

Power is expressed as P = V²/R

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V = supplied voltage

Given P = 600W and V = 30V

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R = 30²/600

R = 900/600

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3 0
1 year ago
The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
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Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

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Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0
2 years ago
A bug starts at point A, crawls 8.0 cm east, then 5.0 cm south, 3.0 west, and 4.0 cm north to point B.
Sholpan [36]

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5cm east& 1cm west from A

Explanation:

https://brainly.ph/question/2753392

7 0
1 year ago
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