Charge on can A is positive.
Charge on can C is negative.
Punctuation and capitalization are very useful things to pay attention to and this question would be a lot easier to understand if you had actually used both capitalization and punctuation. If I'm understanding the question, you have 3 metal can that are insulated from the environment and initially touching each other in a straight line. Then a negatively charged balloon is brought near, but not touching one of the cans in that line of cans. While the balloon is near, the middle can is removed. Then you want to know the charge on the can that was nearest the balloon and the charge on the can that was furthermost from the balloon.
As the balloon is brought near to can a, the negative charge on the balloon repels some of the electrons from can a (like charges repel). Some of those electrons will flow to can b and in turn flow to can c. Basically you'll have a charge gradient that's most positive on that part of the can that's closest to the balloon, and most negative on the part of the cans that's furthest from the balloon. You then remove can B which causes cans A and C to be electrically isolated from each other and prevents the flow of elections to equalize the charges on cans A and C when the balloon is removed. So you're left with a deficiency of electrons on can A, so can A will have a positive overall charge, and an excess of electrons on can C, so can C will have a negative overall charge.
Answer:
, 
Explanation:
The jet is flying at constant velocity: this means that its acceleration is zero, so the net force acting on the jet is also zero.
Therefore, we can write:
where
is the thrust force generated by each engine of the jet
is the drag force
Solving for Fd,
The velocity of the jet is
So, the rate at which the drag force does work (which is the power) is
and substituting
we find
Converting into horsepower,
Answer:
The net force on the scooter is 95 N to the left.
Explanation:
Lizzie is pushing with 75 N of force to the left, so the force is a vector with 75N of magnitude and to the left.
Alex is helping with 20 N to the left, so the force is a vector with 20 N magnitude and to the left.
When we add vectors, vectors that point in the same direction add up and vectors that point in opposite directions are subtracted.
Hence, the net force is equal to:
F=75 N + 20 N=95 N
As both forces point to the left, the net force is also to the left.
Let there be N number of wires.
Maximum tension a wire can withstand = 100 lb
so, Total tension N wires can withstand = 100 N
now, total tension in N wires = Maximum weight of bucket
100 N = W
so, W = 100N
W is the weight of bucket and 100N is its maximum value.
Answer: -2.5
Explanation:
1/2(-5)= -2.5
-2.5(1)= -2.5
Got it right in Khan Academy. You’re welcome.
