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pav-90 [236]
2 years ago
9

Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink?

Physics
2 answers:
pantera1 [17]2 years ago
6 0
<span>the rock will sink because it is more dense than water.</span>
bearhunter [10]2 years ago
5 0

Answer:

It will sink

Explanation:

An object in the water can float only if its density is lower than the density of the water.

In fact, for an object completely immersed in water, there are two forces acting on it:

- Its weight, W=mg=\rho_o V g, downward, where \rho_o is the density of the object, V its volume and g the gravitational acceleration

- The buoyant force, B=\rho_w V g, upwards, there \rho_w is the density of the water

We see that when the density of an object is larger than the density of the water, \rho_o > \rho_w, the weight is greater than the buoyant force, W>B, so the object sinks.

In this case, the rock has a density of 1.73 g/cm3, while water has a density of 1.0 g/cm^3, so the rock will sink.


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what will be the resistivity of a metal wire of 2m length and 0.6mm in a diameter ,if the resistance of the wire is 50ohm . find
Maru [420]

Answer:Resistivity of the wire is 7.065 × 10^-8 Ω m.

Explanation:

I have no idea i just googled it

5 0
1 year ago
Solenoid 2 has twice the diameter, twice the length, and twice as many turns as solenoid 1. How does the field B2 at the center
klemol [59]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  option 3

Explanation:

From the question we are told that

   The diameter of solenoid 1 is  d_1

   The length of solenoid 1 is   L_1

    The  number of turns of solenoid is  N_1

   The diameter of solenoid 2 is  d_2 = 2d_1

   The length of solenoid 2 is   L_2 = 2L_1

    The  number of turns of solenoid  2 is    N_2 = 2 N_1

Generally the magnetic in a solenoid is mathematically represented as

     B  =  \frac{\mu_o *  N  *  I }{L}

From this equation we see that

     B  \ \alpha \  \frac{N}{L}

     B   =  C   \frac{N}{L}

Here C stands for constant

=>   C =  \frac{B *  \frac{L}{N}

=>    \frac{B_1 *  \frac{L_1}{N_1}   = \frac{B_2 *  \frac{L_2}{N_2}

=>  \frac{B_1}{B_2 }  =  \frac{N_1 L _2}{ N_2L_1}

=>   \frac{B_1}{B_2 }  =  \frac{N_1 * (2 L_1)}{ (2 N_2)L_1}

=>   \frac{B_1}{B_2 }  =  1

=>   B_2 = B_1

4 0
2 years ago
If the blocks are released from rest, which way does the 10 kg block slide, and what is its acceleration? enter a positive value
anyanavicka [17]
<span>Let m1=10kg and m2=5kg and for our calculations assume right is positive and up is positive (note: for block hanging, the x axis is vertical so tilt your head to help) For m1 Sigma Fx = ma T - m1gsin35 = m1a where T = tension For m2 m2g - T = m2a Add equation together m1a + m2a = T-m1gsin35 + m2g - T a(m1 + m2) = m2g - m1gsin35 a= (5*9.8 - 10*9.8*sin35)/(10 + 5) a= -0.48m/s/s So the system is moving in the opposite direction of our set coordinate system where we said right positive, its negative so its moving left therefore down the ramp</span>
6 0
2 years ago
Read 2 more answers
Air "breaks down" when the electric field strength reaches 3×106n/c, causing a spark. a parallel-plate capacitor is made from tw
aalyn [17]
Ok, I think this is right but I am not sure:
 Q = ϵ
 0AE
A= π π
 r^2

=(8.85x10^-12 C^2/Nm^2)
( π π (0.02m)^2)
(3x10^6 N/C) =3.3x10^-8 C = 33nC N = Q/e = (3.3x10^-8 C)/(1.60x10^-19 C/electron) = 2.1x10^11 electrons


4 0
1 year ago
In the sport of curling, large smooth stones are slid across an ice court to land on a target. Sometimes the stones need to move
lara31 [8.8K]

Answer:

To increase kinetic friction, the amount of fine water droplets sprayed before the game is limited.

To reduce kinetic friction. increase the amount of fine water droplets during pregame preparation and sweeping in front of the curling stones.

Explanation:

In curling sports, since the ice sheets are flat, the friction on the stone would be too high and the large smooth stone would not travel half as far. Thus controlling the amount of fine water droplets sprayed before the game is limited pregame is necessary to increase friction.

On the other hand, reducing ice kinetic friction involves two ways. The first way is adding bumps to the ice which is known as pebbling. Fine water droplets are sprayed onto the flat ice surface. These droplets freeze into small "pebbles", which the curling stones "ride" on as they slide down the ice. This increases contact pressure which lowers the friction of the stone with the ice. As a result, the stones travel farther, and curl less.  

The second way to reduce the kinetic friction is sweeping in front of the large smooth stone. The sweeping action quickly heats and melts the pebbles on the ice leaving a film of water. This film reduces the friction between the stone and ice.

8 0
1 year ago
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