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2 years ago

9

Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink?

2 answers:

pantera1 [17]2 years ago

6 0

<span>the rock will sink because it is more dense than water.</span>

bearhunter [10]2 years ago

5 0

Answer:

It will sink

Explanation:

An object in the water can float only if its density is lower than the density of the water.

In fact, for an object completely immersed in water, there are two forces acting on it:

- Its weight, $W=mg=\rho_o V g$ , downward, where $\rho_o$ is the density of the object, V its volume and g the gravitational acceleration

- The buoyant force, $B=\rho_w V g$ , upwards, there $\rho_w$ is the density of the water

We see that when the density of an object is larger than the density of the water, $\rho_o > \rho_w$ , the weight is greater than the buoyant force, $W>B$ , so the object sinks.

In this case, the rock has a density of 1.73 g/cm3, while water has a density of 1.0 g/cm^3, so the rock will sink.

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There have been several proposed atomic models during the last 150 years. Which model best illustrates the Bohr model. This mode

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<span>Despite the Quantum Mechanical Model treating the electron mathematically as a wave rather than fixed patterns, the Quantum Mechanical model best illustrates the Bohr model because both models of the atom assign specific energies to an electron.</span>

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A monkey weighs 6.00 x 102 N and swings from vine to vine. As the monkey grabs a new vine, both vines make an angle of 35.0° wit

zmey [24]

Answer:

$T=366.23\ N$

Explanation:

Given:

mass of monkey, $w=600\ N$

angle of vine from the vertical, $\theta=35^{\circ}$

Now follow the schematic to understand the symmetry and solution via Lami's theorem.

<u>The weight of the monkey will be balanced equally by the tension in both the vines:</u>

Using Lami's Theorem:

$\frac{w}{sin\ 70^{\circ}} =\frac{T}{sin\ 145^{\circ}}$

$\frac{600}{sin\ 70^{\circ}} =\frac{T}{sin\ 145^{\circ} }$

$T=366.23\ N$

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2 years ago

A baby elephant is stuck in a mud hole. to help pull it out, game keepers use a rope to apply a force f with arrowa, as part a o

Julli [10]

The two forces should be equal therefore:

2.10 * Fa = Fa + 2 * F * cos 18

simplifying the right side:

2.10 * Fa = Fa + 1.902 * F

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1 year ago

When a mass of 25 g is attached to a certain spring, it makes 20 complete vibrations in 4.0 s. what is the spring constant of th

earnstyle [38]

Answer: The spring of the spring is 25 N/m.

Explanation:

Mass of the body = 25 g= 0.025 kg (1 kg = 1000 g)

Oscillation is 4 sec = 20

Oscillation in 1 sec = $\frac{20}{4}=5$

Frequency of the vibration of the spring = $5 s^{-1}=5 Hz$

Force constant can be calculated bu using the relation between the frequency and, mass and spring constant 'k'

$Frequency=\frac{1}{2\pi}\times \sqrt{\frac{k}{m}}$

$5 s^{-1}=\frac{1}{2\times 3.14}\times \sqrt{\frac{k}{0.025 kg}}$

$k=24.649 N/m\approx 25 N/m$

The spring of the spring is 25 N/m.

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2 years ago

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A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a 1.19 meter high desk. How far awa

kipiarov [429]

Answer:

2.45 m

Explanation:

First of all, we have to calculate the time of flight of the book, by using the equation for the vertical motion:

$h=\frac{1}{2}gt^2$

where

h = 1.19 m is the vertical distance covered by the book

g = 9.8 m/s^2 is the acceleration of gravity

t is the time of flight

Solving for t,

$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(1.19)}{9.8}}=0.49 s$

Now we can find the horizontal distance covered by the book, which is given by

$d=v_x t$

where

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Substituting,

$d=(5.0)(0.49)=2.45 m$

So the book lands 2.45 m away.

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2 years ago