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madreJ [45]
2 years ago
14

The suspension cable of a 1,000 kg elevator snaps, sending the elevator moving downward through its shaft. The emergency brakes

of the elevator stop the elevator shortly before it reaches the bottom of the shaft. If the elevator fell a distance of 100 m starting from rest, the heat that the brakes must dissipate to bring the elevator safely to rest is (A) 100 J (B) 1,000 J (C) 10,000 J (D) 100,000 J (E) 1,000,000 J
Physics
1 answer:
tester [92]2 years ago
4 0

Answer:

option (E) 1,000,000 J

Explanation:

Given:

Mass of the suspension cable, m = 1,000 kg

Distance, h = 100 m

Now,

from the work energy theorem

Work done by the gravity = Work done by brake

or

mgh = Work done by brake

where, g is the acceleration due to the gravity = 10 m/s²

or

Work done by brake  = 1000 × 10 × 100

or

Work done by brake = 1,000,000 J

this work done is the release of heat in the brakes

Hence, the correct answer is option (E) 1,000,000 J

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would an elephant standing on one leg exert a higher force on a scale than an elephant on four legs. why​
zlopas [31]

Answer:

no becaus force is mass multiplied by acceleration. the mass of the elephant does not change

7 0
2 years ago
A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction
Vaselesa [24]

Answer:

H=1020.12m

Explanation:

From a balance of energy:

\frac{m*Vo^2}{2} -mg*H=-Ff*d   where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.

The relation between H and d is given by:

H = d*sin(30)   Replace this into our previous equation:

\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*N*d

From a sum of forces:

N -mg*cos(30) = 0    =>  N = mg*cos(30)   Replacing this:

\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*mg*cos(30)*d   Now we can solve for d:

d = 2040.23m

Thus H = 1020.12m

6 0
1 year ago
Read 2 more answers
Which is a correct representation of .000025 in scientific notation?
lidiya [134]

0.000025 → 2.5 × 10⁻⁵ → 2.5E-5

<h3>Further explanation</h3>

Scientific notation represents the precise way scientists handle exceptionally abundant digits or extremely inadequate numbers in the product of a decimal form of number and powers of ten. Put differently, such numbers can be rewritten as a simple number multiplied by 10 raised to a certain exponent or power. It is a system for expressing extremely broad or exceedingly narrow digits compactly.

Scientific notation should be in the form of  

\boxed{ \ a \times 10^n \ }

where  

\boxed{ \ 1 \leq a \ < 10 \ }

The number 'a' is called 'mantissa' and 'n' the order of magnitude.

From the key question that is being asked, we face the standard form of 0.000025.

\boxed{ \ 0.000025 = \frac{25}{1,000,000} \ }

The coefficient (or mantissa), i.e. 25, is still outside of 1 ≤ a < 10. Both the numerator and denominator are divided by 10.

\boxed{ \ 0.000025 = \frac{2.5}{100,000} \ }

The denominator consists precisely of five zero digits.

Hence, 0,000025 is written in scientific notation as  \boxed{\boxed{ \ 2.5 \times 10^{-5} \ or \ 2.5E - 5 \ }}

The inverse of scientific notation is the standard form. To promptly change scientific notation into standard form, we reverse the process, move the decimal point to the right or left. This expanded form is called the standard form.

<u>A notable example:</u>

\boxed{ \ 3.0 \times 10^{8} \ Hz \ \rightarrow 300,000,000 \ Hz \ or \ 300 \ MHz}

<h3>Learn more</h3>
  1. 0.00069 written in scientific notation brainly.com/question/7263463
  2. Express the pill’s mass in 0.0005 grams using scientific notation or in milligrams brainly.com/question/493592
  3. What 3 digits are in the units period of 4,083,817 brainly.com/question/558692

Keywords: which is, a correct representation, 0.000025, in scientific notation, expanded form, exponent, base, standard form, mantissa, the order of magnitude, power, decimal, very large, small, figures, abundant digits, inadequate

6 0
2 years ago
Read 2 more answers
A Body OF Volume 36cc Floats With 3/4 of its volume submerged in water . The density Of Body is
Radda [10]

Answer:

Density of body = 0.25g/cc

Explanation:

Given:

Volume submerged in water = 3/4

Find:

Density Of Body

Computation:

Density of body = fraction of body in liquid x density of water

Density of body = [1-3/4]1

Density of body = 0.25g/cc

8 0
1 year ago
A soap bubble has a diameter of 4mm .Cakculate the pressure inside it if the atmospheric pressure outside is 10^5Nm^2 . The surf
Kipish [7]
Look it up it will give the right anwser
3 0
2 years ago
Read 2 more answers
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