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2 years ago

A school bus covers a distance of 7200 m in 1800 s. Calculate its speed.

Physics

1 answer:

telo118 [61]2 years ago

8 0

Answer:

Speed = 4 m/sec

Explanation:

Speed = Distance / Time

Where Distance = 7200 m and Time = 1800 s

Speed = 7200 m / 1800 sec

Speed = 4 m/sec

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Answer: Hello your question is incomplete attached below is the complete question

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Explanation:

To determine the scalar components Ra

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therefore : Ra = $\frac{sin120^o * 750}{sin 35^o}$ = 1132 N

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$\frac{Rb}{sin 25^o} = \frac{750}{sin 35^o}$

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To determine the orthogonal projection Pa of R onto

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MariettaO [177]

Answer:

Explanation:

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$\Delta H=m\times C\times \Delta T$

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m is the mass

C is the specific heat capacity

$\Delta T$

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1 year ago

Imagine you’re driving along a road and you approach a bridge. You notice a sign that reads, “Bridge freezes before road.” Why d

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<u>Answer:</u>

<h3>During wet and freezing temperatures, ice is able to form at a faster pace on bridges because freezing winds blow from above and below and both sides of the bridge, causing heat to quickly escape. The road freezes slower because it is merely losing heat through its surface.</h3>

<u>Sources:</u>

-- https://intblog.onspot.com/en-us/why-do-bridges-become-icy-before-roads

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-- https://www.accuweather.com/en/accuweather-ready/why-bridges-freeze-before-roads/687262

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1 year ago

The drawing shows the top view of a door that is 1.68 m wide. two forces are applied to the door as indicated. what is the magni

jekas [21]

First, torque is equal to force times the distance. for the first force that is applied, the torque is zero because is applied at the hinge. so the net torque:
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1 year ago

When a car drives along a "washboard" road, the regular bumps cause the wheels to oscillate on the springs. (What actually oscil

marishachu [46]

Answer:

a) 40,000 N/m

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part a)

First in order to estimate the spring constant k, we need to know the expression or formula to use in this case:

k = ΔF / Δx

Where:

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Δx: the sinking of the car, which is 2 cm or 0.02 m.

With this data, and knowing that there are four mens, replace the data in the above formula:

W = 80 * 10 = 800 N

This is the weight for 1 man, so the 4 men together would be:

W = 800 * 4 = 3200 N

So, replacing this data in the formula:

k = 3200 / 0.02 = 160,000 N/m

This means that one spring will be:

k' = 160,000 / 4 = 40,000 N/m

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k^n = 2k

To get the frequency, we need to know the angular speed of the car with the following expression:

wo = √k^n / M

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Replacing the data:

wo = √2 * 40,000 / 50 = 40 rad/s

And the frequency:

f = wo/2π

f = 40 / 2π = 6.37 Hz

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V = x * t

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V = 0.8 * 6 =

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2 years ago