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JulsSmile [24]
2 years ago
15

Subatomic particles that do not possess any charge but provide mass to atoms are called

Physics
1 answer:
WARRIOR [948]2 years ago
6 0

Answer:

Neutrons

Explanation:

Neutrons are subatomic particles that are electrically neutral and possess no charge in them.

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A spaceship of mass 8600 kg is returning to Earth with its engine turned off. Consider only the gravitational field of Earth. Le
Katyanochek1 [597]

Answer:

\Delta KE = 4.20\times 10^{13}\ J

Explanation:

given,

mass of spaceship(m) = 8600 Kg

Mass of earth = 5.972 x 10²⁴ Kg

position of movement of space ship

R₁ = 7300 Km

R₂ = 6700 Km

the kinetic energy of the spaceship increases by = ?

Increase in Kinetic energy = decrease in potential energy

    \Delta KE = GMm (\dfrac{1}{R_2}-\dfrac{1}{R_1})

    \Delta KE = GMm (\dfrac{R_1-R_2}{R_2R_1})

    \Delta KE = 6.67 \times 10^{-11}\times 5.972 \times 10^{24}\times 8600 (\dfrac{7300 - 6700}{7300 \times 6700})

    \Delta KE = 6.67 \times 10^{-11}\times 5.972 \times 10^{24}\times 8600 (\dfrac{600}{48910000})

    \Delta KE = 4.20\times 10^{13}\ J

5 0
2 years ago
What is the chemical formula for aluminum nitride?<br> A) Al3 <br> B) AlN3 <br> C) Al3N3 <br> D) AlN
OleMash [197]
The answer is c Ai3n3 yea that’s the right answer idk
6 0
2 years ago
Read 2 more answers
How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice
Vilka [71]

Answer:

How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol

A. 108 kJ

B. 102 kJ

C. 5.64 kJ

D. 936 kJ

E. none of the above

<em>5.64 kJ</em>

Explanation:

The Heat of fusion is the heat energy required to dissolve a given mass of ice at melting point.

<h3>Step by Step Calculation</h3>

The heat energy required to dissolve ice can be calculated using the expression below;

Q = ΔH_{f} x m ...............................................1

where Q is the heat energy required;

           ΔH_{f}  is the heat of fusion for ice;

           m is the mole

All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol .

<em>This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;</em>

m = \frac{16.87g}{18.015g/mol}

m = 0.9364 mole of ices

Now the parameters are complete, we are given;

ΔH_{f}  = 6.02 kJ/mol

m = 0.9364 mol

Q =?

Substituting into equation 1, we have

Q =  6.02 kJ/mol x 0.9364 mol

Q = 5.64 kJ

<em>Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ</em>

5 0
2 years ago
You have found a treasure map that directs you to start at a hollow tree, walk 300 meters directly north, turn and walk 500 mete
Dmitry_Shevchenko [17]

Answer:633 m

Explanation:

First we have moved 300 m in North

let say it as point a and its vector is 300\hat{j}

after that we have moved 500 m northeast

let say it as point b

therefore position of b with respect to a is

r_{ba}=500cos(45)\hat{i}+500sin(45)\hat{j}

Therefore position of b w.r.t to origin is

r_b=r_a+r_{ba}

r_b=300\hat{j}+500cos(45)\hat{i}+500sin(45)\hat{j}

r_b=500cos(45)\hat{i}+\left [ 250\sqrt{2}+300\right ]\hat{j}

after this we moved 400 m 60^{\circ} south of east i.e. 60^{\circ} below from positive x axis

let say it as c

r_{cb}=400cos(60)\hat{i}-400sin(60)\hat{j}

r_c=r_{b}+r_{cb}

r_c=500cos(45)\hat{i}+\left [ 250\sqrt{2}+300\right ]\hat{j}+400cos(60)\hat{i}-400sin(60)\hat{j}

r_c=\left [ 250\sqrt{2}+200\right ]\hat{i}+\left [ 250\sqrt{2}+300-200\sqrt{3}\right ]\hat{j}

magnitude is \sqrt{\left [ 250\sqrt{2}+200\right ]^2+\left [ 250\sqrt{2}+300-200\sqrt{3}\right ]^2}

=633.052

for directiontan\theta =\frac{250\sqrt{2}+300-200\sqrt{3}}{250\sqrt{2}+200}

tan\theta =\frac{307.139}{553.553}

\theta =29.021^{\circ} with x -axis

7 0
1 year ago
A hot piece of iron is thrown into the ocean and its temperature eventually stabilizes. Which of the following statements concer
777dan777 [17]

Answer:

E. The ocean gains more entropy than the iron loses.

Explanation:

When there is a spontaneous process , entropy of the system increases . Here hot iron is losing entropy and ocean is gaining entropy . Net effect will be gain of entropy . That means entropy gained by ocean is more than entropy lost by iron .

Hence option E is correct .

8 0
1 year ago
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