Answer:

Explanation:
given,
mass of spaceship(m) = 8600 Kg
Mass of earth = 5.972 x 10²⁴ Kg
position of movement of space ship
R₁ = 7300 Km
R₂ = 6700 Km
the kinetic energy of the spaceship increases by = ?
Increase in Kinetic energy = decrease in potential energy





The answer is c Ai3n3 yea that’s the right answer idk
Answer:
How much energy does it take to melt a 16.87 g ice cube? ΔHfus = 6.02 kJ/mol How much energy does it take to melt a 16.87 g ice cube? = 6.02 kJ/mol
A. 108 kJ
B. 102 kJ
C. 5.64 kJ
D. 936 kJ
E. none of the above
<em>5.64 kJ</em>
Explanation:
The Heat of fusion is the heat energy required to dissolve a given mass of ice at melting point.
<h3>
Step by Step Calculation</h3>
The heat energy required to dissolve ice can be calculated using the expression below;
Q = ΔH
x m ...............................................1
where Q is the heat energy required;
ΔH
is the heat of fusion for ice;
m is the mole
All the parameters above are provided in the question except m, so to get m we use the molar mass of water (also for ice) which is 18.01528 g/mol
.
<em>This means that 18.01528 g of ice is contained in one mole, therefore the mole for 16.87 g of ice is given as;</em>

m = 0.9364 mole of ices
Now the parameters are complete, we are given;
ΔH
= 6.02 kJ/mol
m = 0.9364 mol
Q =?
Substituting into equation 1, we have
Q = 6.02 kJ/mol x 0.9364 mol
Q = 5.64 kJ
<em>Therefore, the energy required to melt 16.87 g of ice is 5.64 kJ</em>
Answer:633 m
Explanation:
First we have moved 300 m in North
let say it as point a and its vector is 
after that we have moved 500 m northeast
let say it as point b
therefore position of b with respect to a is
r
Therefore position of b w.r.t to origin is


![r_b=500cos(45)\hat{i}+\left [ 250\sqrt{2}+300\right ]\hat{j}](https://tex.z-dn.net/?f=r_b%3D500cos%2845%29%5Chat%7Bi%7D%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300%5Cright%20%5D%5Chat%7Bj%7D)
after this we moved 400 m
south of east i.e.
below from positive x axis
let say it as c


![r_c=500cos(45)\hat{i}+\left [ 250\sqrt{2}+300\right ]\hat{j}+400cos(60)\hat{i}-400sin(60)\hat{j}](https://tex.z-dn.net/?f=r_c%3D500cos%2845%29%5Chat%7Bi%7D%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300%5Cright%20%5D%5Chat%7Bj%7D%2B400cos%2860%29%5Chat%7Bi%7D-400sin%2860%29%5Chat%7Bj%7D)
![r_c=\left [ 250\sqrt{2}+200\right ]\hat{i}+\left [ 250\sqrt{2}+300-200\sqrt{3}\right ]\hat{j}](https://tex.z-dn.net/?f=r_c%3D%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B200%5Cright%20%5D%5Chat%7Bi%7D%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300-200%5Csqrt%7B3%7D%5Cright%20%5D%5Chat%7Bj%7D)
magnitude is ![\sqrt{\left [ 250\sqrt{2}+200\right ]^2+\left [ 250\sqrt{2}+300-200\sqrt{3}\right ]^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B200%5Cright%20%5D%5E2%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300-200%5Csqrt%7B3%7D%5Cright%20%5D%5E2%7D)
=633.052
for direction

with x -axis
Answer:
E. The ocean gains more entropy than the iron loses.
Explanation:
When there is a spontaneous process , entropy of the system increases . Here hot iron is losing entropy and ocean is gaining entropy . Net effect will be gain of entropy . That means entropy gained by ocean is more than entropy lost by iron .
Hence option E is correct .