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2 years ago

Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.

Physics

1 answer:

nirvana33 [79]2 years ago

3 0

Answer: The answer to the question is 0.25 ohms

Explanation:

R = u x/A .......1

where u is chosen as the resistivity of

the rod, A is area of the rod and x is

chosen as the length of the rod.

Let R* be the resistance of the

lengths of the rod across the adjoints

Then R* = u1/4.......2

Comparing equation 1 and 2

R* = 1/4

=0.25ohms

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A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly hori

Nutka1998 [239]

Answer:

The cannonball fly horizontally before it strikes the ground, S = 323.25 m

Explanation:

Given data,

The height of the cliff, h = 80 m

The horizontal velocity of the cannonball, Vₓ = 80 m/s

The range of the cannon ball with initial vertical velocity is zero is given by the formula,

$S=\frac{V_{x}\sqrt{2gh}}{g}$

$S=\frac{80\sqrt{2\times9.8\times80}}{9.8}$

S = 323.25 m

Hence, the cannonball fly horizontally before it strikes the ground, S = 323.25 m

7 0

1 year ago

Read 2 more answers

An airliner of mass 1.70×105kg1.70×105kg lands at a speed of 75.0 m/sm/s. As it travels along the runway, the combined effects o

Karo-lina-s [1.5K]

Answer:

The airliner travels 1.65 km along the runway before coming to a halt.

Explanation:

Given

Resistive forces = (2.90 × 10⁵) N = 290000 N

Mass of the airliner = (1.70 × 10⁵) kg = 170000 kg

Velocity of airliner = 75 m/s

Let the distance over moved by the airliner be equal to d

According to the work-energy theorem, the work done by the resistive forces in stopping the airliner is equal to the travelling kinetic energy of the airliner.

Work done by the resistive forces = (290000) × d = (290,000d) J

Kinetic energy of the airliner = (1/2)(170000)(75²) = 478,125,000 J

290000d = 478,125,000

d = (478,125,000/290,000)

d = 1648.7 m = 1.65 km

Hope this helps!!!

4 0

2 years ago

If the average speed of an orbiting space shuttle is 27 800 km/h, determine the time required for it to circle Earth. Assume tha

balu736 [363]

Answer:

t = 1.51 hours

Explanation:

given,

Speed of space shuttle. v = 27800 Km/h

Radius of earth, R = 6380 Km

height of shuttle above earth, h = 320 Km

Total radius of the shuttle orbit

r' = R + h

r' = 6380 + 320

r' = 6700 Km

distance, d = 2 π r

d = 2 π x 6700

$time = \dfrac{distance}{speed}$

$time = \dfrac{2\pi\times 6700}{27800}$

t = 1.51 hours

Time require by the shuttle to circle the earth is equal to 1.51 hr.

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1 year ago

A gannet is a seabird that fishes by diving from a great height. part a if a gannet hits the water at 32 m/s , what height did i

lutik1710 [3]

93 if this is reasaning but make sure

6 0

2 years ago

A 0.500-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wa

lana66690 [7]

Answer:

E) I = 18.4 N.s

Explanation:

For this exercise let's use momentum momentum

I = Δp = $p_{f}$ - p₀

The energy of the stone is only kinetic

K = ½ m v²

The initial energy is Ko and the final is 70% Ko

$K_{f}$ = 0.70 K₀

energy equation

$K_{f}$ = 0.7 ½ m v₀²

You can also write

$K_{f}$ = ½ m vf²

½ m vf² = ½ m (0.7 v₀²)

$v_{f}$ = v₀ √ 0.7

Now we can calculate and imposed

I = m (-vo √0.7) - m vo

I = m vo (1 +√0.7

I = 0.5000 20.0 (1.8366)

I = 18.4 N.s

5 0

1 year ago

Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.​

Resistance of rod is 1 ohm. It is bent in the form of square. The resistance across adjoint corners is.