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Nataly [62]
2 years ago
7

15 PLEASE HELP

Physics
1 answer:
sashaice [31]2 years ago
6 0

Answer:

Ok, her position changed over time since the road is curved.

The velocity changed since the direction is changing

AccelerTion: theres a change in velocity since the direction changes

Direction: changed over time

Displacement : difference between 1st and final position

Explanation:

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hows a map of Olivia's trip to a coffee shop. She gets on her bike at Loomis and then rides south 0.9mi to Broadway. She turns e
sweet-ann [11.9K]

The question is incomplete. Here is the complete question.

The map (in the attachment) shows Olivia's trip to the coffee shop. She gets on her bike at Loomis and then rides south 0.9mi to Broadway. She turns east onto Broadway, rides 0.8mi to where Broadway turns, and then continues another 1.4mi to the shop.

What is the magnitude of the total displacement of her trip?

Whta is the direction of the total displacement of her trip?

Answer: Magnitude = 2.6mi

              Direction: 54.65° east

Explanation: <u>Displacement</u> is the change in postition of a moving object.

There are a few ways to determine total displacement. For this case, the Perpendicular Components of a Vector method will be used.

For this method, total displacement is given by:

\Delta d_{t}=\sqrt{(\Delta d_{x})^{2}+(\Delta d_{y})^{2}}

\theta=tan^{-1}(\frac{\Delta d_{y}}{\Delta d_{x}})

\Delta d_{x} is the x-component of total displacement and it is the sum of each individual x-components;

\Delta d_{y} is the y-component of total displacement and it is the sum of each individual y-components;

θ is the angle the resulting displacement;

For Olivia's trip, there are no x-component of the first part and for the third part, the path she bikes is a hypotenuse of a right triangle. So, that right triangle's x-component is:

sin30=\frac{x}{1.4}

\frac{1}{2} =\frac{x}{1.4}

x = 0.7

Then,

\Delta d_{x} = 0 + 0.8 + 0.7

\Delta d_{x} = 1.5

Related to y, there are no y-component in the second part of Olivia's trip and for the third part:

cos30=\frac{y}{1.4}

\frac{\sqrt{3} }{2} =\frac{y}{1.4}

y = 1.21

Then,

\Delta d_{y} = 0.9 + 0 + 1.21

\Delta d_{y} = 2.11

Total displacement is

\Delta d_{t}=\sqrt{(1.5)^{2}+(2.11)^{2}}

\Delta d_{t}=\sqrt{6.7021}

\Delta d_{t}= 2.6

Magnitude of Olivia's total displacement is 2.6mi

On the map, joining the initial and final points gives a vector pointing towards east at angle:

\theta=tan^{-1}(\frac{2.11}{1.5})

\theta=tan^{-1}(1.41)

θ = 54.65°

Direction of total displacement is 54.65° East.

6 0
2 years ago
A star is located at a distance of about 100 million light years from Earth. An astronomer plans to measure the distance of the
nlexa [21]
<span>d. The parallaxes beyond a few thousand light years are
too small to be measured with common instruments.

I'm not sure that parallax can even be used out to a few
thousand light years.

The NEAREST star to Earth has the BIGGEST parallax.
The star is Alpha Centauri.  It's only 4 light years away
from us, and its parallax is  0.000206 of a degree !
I have no idea how astronomers can measure angles
so small ... and that's the BIGGEST parallax angle of
ANY star.</span>
5 0
2 years ago
When a car goes around a circular curve on a horizontal road at constant speed, what force causes it to follow the circular path
Reil [10]
Centripetal force allows cars to follow a circular path.
4 0
2 years ago
Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1
nika2105 [10]

Answer:

Velocity, v = 2.50 m/s

Explanation:

Given that,

Mass of the ball, m = 7.26 kg

Height above the ground, h = 2.1 m

Mechanical energy of the ball, T = 172.1 J

To find,

The velocity of the ball at the given point.

Solution,

The sum of potential energy and the kinetic energy is called the mechanical energy of an object. It is given by :

T=K+P

K is the kinetic energy

P is the potential energy

T=\dfrac{1}{2}mv^2+mgh

On rearranging the above equation,

v^2=\dfrac{2(T-mgh)}{m}

v^2=\dfrac{2(172.1-7.26\times 9.8\times 2.1)}{7.26}

v = 2.50 meters

Therefore, the velocity of the ball at the given point is 2.50 m/s.

7 0
2 years ago
Read 2 more answers
A glider is gliding through the air at a height of 416 meters with a speed of 45.2 m/s. The glider dives to a height of 278 mete
Verdich [7]

Answer:

<em>The glider's new speed is 68.90 m/s</em>

Explanation:

<u>Principle Of Conservation Of Mechanical Energy</u>

The mechanical energy of a system is the sum of its kinetic and potential energy. When the only potential energy considered in the system is related to the height of an object, then it's called the gravitational potential energy. The kinetic energy of an object of mass m and speed v is

\displaystyle K=\frac{1}{2}mv^2

The gravitational potential energy when it's at a height h from the zero reference is

U=mgh

The total mechanical energy is

M=K+U

\displaystyle M=\frac{1}{2}mv^2+mgh

The principle of conservation of mechanical energy states the total energy is constant while no external force is applied to the system. One example of a non-conservative system happens when friction is considered since part of the energy is lost in its thermal manifestation.

The initial conditions of the problem state that our glider is glides at 416 meters with a speed of 45.2 m/s. The initial mechanical energy is

\displaystyle M_1=\frac{1}{2}m(45.2)v_o^2+m(9.8)(416)

Operating in terms of m

\displaystyle M_1=1021.52m+4076.8m

\displaystyle M_1=5098.32m

Then we know the glider dives to 278 meters and we need to know their final speed, let's call it v_f. The final mechanical energy is

\displaystyle M_2=\frac{1}{2}mv_f^2+m(9.8)(278)

Operating and factoring

\displaystyle M_2=m(\frac{1}{2}v_f^2+2724.4)

Both mechanical energies must be the same, so

\displaystyle m(\frac{1}{2}v_f^2+2724.4)=5098.32m

Simplifying by m and rearranging

\displaystyle \frac{v_f^2}{2}=5098.32-2724.4

Computing

v_f=\sqrt{4747.84}=68.90\ m/s

The glider's new speed is 68.90 m/s

8 0
2 years ago
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