Explanation:
Initial time, t₁ = 2:30 pm
Final time, t₂ = 2:30:45
We need to find the motion of students in terms of time. Final time is 45 seconds more than the initial time.
Change in time,
Hence, this is the required solution.
Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1
2 answers:
Answer:
Velocity, v = 2.50 m/s
Explanation:
Given that,
Mass of the ball, m = 7.26 kg
Height above the ground, h = 2.1 m
Mechanical energy of the ball, T = 172.1 J
To find,
The velocity of the ball at the given point.
Solution,
The sum of potential energy and the kinetic energy is called the mechanical energy of an object. It is given by :
K is the kinetic energy
P is the potential energy
On rearranging the above equation,
v = 2.50 meters
Therefore, the velocity of the ball at the given point is 2.50 m/s.
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Answer:
y = 54.9 m
Explanation:
For this exercise we can use the relationship between the work of the friction force and mechanical energy.
Let's look for work
W = -fr d
The negative sign is because Lafourcade rubs always opposes the movement
On the inclined part, of Newton's second law
Y Axis
N - W cos θ = 0
The equation for the force of friction is
fr = μ N
fr = μ mg cos θ
We replace at work
W = - μ m g cos θ d
Mechanical energy in the lower part of the embankment
Em₀ = K = ½ m v²
The mechanical energy in the highest part, where it stopped
= U = m g y
W = ΔEm = - Em₀
- μ m g d cos θ = m g y - ½ m v²
Distance d and height (y) are related by trigonometry
sin θ = y / d
y = d sin θ
- μ m g d cos θ = m g d sin θ - ½ m v²
We calculate the distance traveled
d (g syn θ + μ g cos θ) = ½ v²
d = v²/2 g (sintea + myy cos tee)
d = 9.8 12.6 2/2 9.8 (sin16 + 0.128 cos 16)
d = 1555.85 /7.8145
d = 199.1 m
Let's use trigonometry to find the height
sin 16 = y / d
y = d sin 16
y = 199.1 sin 16
y = 54.9 m
Answer:
Explanation:
Height reached by the object after push off is given as
now we have
now we know that this push last for total distance of 0.18 m
so during the push we will have
now in terms of g = 9.81 m/s/s we have