Answer:
Option A; ITS SURFACE IS COOLER THAN THE SURFACE OF THE SUN.
Explanation:
A red supergiant star is a larger and brighter type of red giant star. Red supergiants are often variable stars and are between 200 to 2,000 times bigger than the Sun. Example is Betelgeuse.
Betelgeuse is one of the largest known stars, it has a diameter of about 700 times the size of the Sun or 600 million miles, it emits almost 7,500 times as much energy as the Sun, it has a rather low surface temperature (6000F compared to the Sun's 10,000F); this means that it has a more cooler surface than the Sun's surface.
This low temperature also means that the star will appear orange-red in color, and the combination of size and temperature makes it a kind of star called a red super giant.
Although, all the statements above are correct, the only one that can be inferred from the red color of Betelgeuse is that ITS SURFACE IS COOLER THAN THE SURFACE OF THE SUN.
Answer:D
Explanation:
Given
mass of object 
Distance traveled 
velocity acquired 
conserving Energy at the moment when object start falling and when it gains 12 m/s velocity
Initial Energy
Final Energy
where 
is friction work if any
Since Friction is Present therefore it is a case of Open system and net external Force is zero
An open system is a system where exchange of energy and mass is allowed and Friction is acting on the object shows that system is Open .
The unit 'mb' means millibar which is equivalent to 1/1000 of 1 bar. To convert the units from bar to atmospheres (atm) and to inches Hg (inHg), we need to know the conversion factors.
a.) 1 atm = 1.01325 bar
0.92 mb(1 bar/1000 mbar)(1 atm/1.01325 bar) =<em> 9.08×10⁻⁴ atm</em>
b.) 1 bar = 29.53 inHg
0.92 mb(1 bar/1000 mbar)(29.53 inHg/1 bar) =<em> 0.027 inHg</em>
The electric force between two objects can be understood by looking at Coulomb's Law. The law states that the electric force is directly proportional to the charges of the 2 objects, and inversely proportional as the square of the distance. This is shown below:
F = (k * Q1 * Q2) / d^2
Where: k = proportionality constant; Q1 = charge of object 1; Q2 = charge of object 2; d = distance between objects.
Given:
F = <span>3.0 × 10^-3 N
Q1 = </span>3.3 × 10^-8 coulombs<span>
Q2 = ?
d = </span><span>6.0 × 10^-2 m
</span><span>k = 9.0 × 10^9
Substituting:
3 x 10^-3 = (9 x 10^9 * 3.3 x 10^-8 * Q2) / (6 x 10^-2)^2
[(</span>3 x 10^-3) * (6 x 10^-2)^2] / [(<span>9 x 10^9) * (3.3 x 10^-8)</span>] = Q2
Q2 = 3.636 x 10^-8 coulombs
