efficiency= [useful energy transferred ÷ total energy supply]×100%
So, [5500÷10000]×100%=0.55×100
=55%
An oven mitt is used to take the tray out of the oven because it’s an insulator.
Answer:
Final Velocity = √(eV/m)
Explanation:
The Workdone, W, in accelerating a charge, 2e, through a potential difference, V is given as a product of the charge and the potential difference
W = (2e) × V = 2eV
And this work is equal to change in kinetic energy
W = Δ(kinetic energy) = ΔK.E
But since the charge starts from rest, initial velocity = 0 and initial kinetic energy = 0
ΔK.E = ½ × (mass) × (final velocity)²
(Velocity)² = (2×ΔK.E)/(mass)
Velocity = √[(2×ΔK.E)/(mass)]
ΔK.E = W = 2eV
mass = 4m
Final Velocity = √[(2×W)/(4m)]
Final Velocity = √[(2×2eV)/4m]
Final Velocity = √(4eV/4m)
Final Velocity = √(eV/m)
Hope this Helps!!!
Answer:
a) V = 1.866 10² V
, b) V = 3.424 10⁵ V
, c) v = 8.1 10⁶ m / s
Explanation:
a) the potential difference is requested to accelerate the electrons up to 2.7% of the speed of light
v = 0.027 c
v = 0.027 3 10⁸
v = 8.1 10⁶ m / s
for this part we can use the conservation of mechanical energy
starting point. When electrons are at rest
Em₀ = U = q V
final point. Electrons with maximum speed
Em_f = K = ½ m v2
Em₀ = Em_{f}
e V = ½ m v²
V = ½ m v² / e
let's calculate
V = ½ 9.1 10⁻³¹ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 1.866 10² V
V = 1866 V
b) if this acceleration protons is the mass of the proton is m_{p} = 1.67 10-27
V = ½ 1.67 10⁻²⁷ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 3.424 10⁵ V
V = 342402 V
c)
this potential difference should give the protons the same speed as the electrons
v = 8.1 10⁶ m / s
