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valentinak56 [21]
2 years ago
12

Assume that the light from the flashlight is light from a star. Identify the spot where the light from this “star” is most conce

ntrated.

Physics
2 answers:
Reptile [31]2 years ago
8 0

Answer:

This is the answer

Explanation:

SCORPION-xisa [38]2 years ago
3 0
<span>The spot where the light is most concentrated would be at the center. The light is most dense at the center of the flashlight. It will show brightly at the center where the light is disbursed.</span>
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Suppose a teenager puts her bicycle on its back and starts the rear wheel spinning from rest to a final angular velocity of 250
shtirl [24]

Answer: a) angular acceleration, a = 5.24rad/s^2

b) time taken for the wheel to stop, ∆t = 0.30s

Explanation:

All shown in the attachment.

3 0
1 year ago
A flat, wide cloud floats horizontally a few kilometers above the surface of Earth. Its lower surface carries a uniform surface
valentinak56 [21]

Answer:

\frac{kQ}{r^2} r^

Explanation:

Electric field strength= Force/unit charge

E= (kQq/r²)/q ₓ r

where r is the unit vector in the direction of unit charge

E= \frac{kQ}{r^2} r^

4 0
1 year ago
What is NOT one of the three primary resources that families have to reach financial goals?
Elodia [21]
What is NOT one of the three primary resources that families have to reach financial goals? It is c) education
8 0
1 year ago
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
1 year ago
A light ray strikes a plane mirror at an angle of 23° to the normal. What is the angle between the reflected ray and the mirror?
tiny-mole [99]

Answer:67^{\circ}

Explanation:

Given

Ray of light incident on plane making an angle of 23^{\circ} with normal

Thus incident angle i=23^{\circ}

So according to the law of incidence is equal to angle of reflection

\angle i=\angle r

thus \angle r=23^{\circ}

and angle between mirror and reflected ray =90^{\circ}-23^{\circ}

=67^{\circ}

4 0
2 years ago
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