Answer:
the new diameter of the third ring = 0.607 mm
Explanation:
Consider the radius of 
bright ring when air is in between the lens and the plate ;
Using the expression: 
for the radius of the bright ring since the liquid (water ) of the refractive index 'n' is now in between the lens and the plate;
where;
= number of fringe
λ = wavelength
R = radius
n = refractive index of water
Now ;
the radius r of the third bright ring when the air is in between lens and plate = 
The new radius of the third bright fringe is 
Calculating the new diameter ; we have:
d(3) = 2(r(3))
d(3) = 2(0.3035)
d = 0.607 mm
Thus, the new diameter of the third ring = 0.607 mm
Answer:
34.17°C
Explanation:
Given:
mass of metal block = 125 g
initial temperature 
= 93.2°C
We know
..................(1)
Q= Quantity of heat
m = mass of the substance
c = specific heat capacity
c = 4.19 for H₂O in 
= change in temperature
Now
The heat lost by metal = The heat gained by the metal
Heat lost by metal = 
Heat gained by the water = 
thus, we have
=
⇒ 
Therefore, the final temperature will be = 34.17°C
T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
<span>When the particles of a medium move with simple harmonic motion, this means the wave is a sinusoidal wave.
Know that a sinusoidal curve can describe either sine or cosine functions (remember your cofunction identities for sine and cosine).</span>
Kinetic energy is calculated through the equation,
KE = 0.5mv²
At initial conditions,
m₁: KE = 0.5(0.28 kg)(0.75 m/s)² = 0.07875 J
m₂ : KE = 0.5(0.45 kg)(0 m/s)² = 0 J
Due to the momentum balance,
m₁v₁ + m₂v₂ = (m₁ + m₂)(V)
Substituting the known values,
(0.29 kg)(0.75 m/s) + (0.43 kg)(0 m/s) = (0.28 kg + 0.43 kg)(V)
V = 0.2977 m/s
The kinetic energy is,
KE = (0.5)(0.28 kg + 0.43 kg)(0.2977 m/s)²
KE = 0.03146 J
The difference between the kinetic energies is 0.0473 J.
