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Eddi Din [679]
2 years ago
8

Fatima is watching her pet cat, Winter, napping in the sun. Fatima is curious about the heart rate of Winter when she is napping

, so she develops this scientific question: Does a cat's heart rate change while it is napping? She decides to develop a hypothesis to test this scientific question. What could Fatima's hypothesis be?
Physics
2 answers:
Vsevolod [243]2 years ago
7 0

Answer:

The correct answer will be-<em>"If a cat is naps, the heart beat rate of cat changes."</em>

Explanation:

A scientific hypothesis is a predictive statement based on the works of an earlier investigation. The hypothesis is considered as a well-educated guess which explains the scientific question in a limit.

The scientific hypothesis is proposed in such a way that it could be tested easily through the experiments which can disprove or prove the hypothesis and explain the question.

In the given question, the predicted hypothesis will be-<em> "If a cat naps, the heartbeat rate of cat changes."</em> which can be measured through the instruments.

svetoff [14.1K]2 years ago
3 0

Answer:

Explanation:

There are two hypotheses she could test:

A cat's heart rate changes while it is napping.

A cat's heart rate does not change while it is napping.

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A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is t
Blababa [14]

Answer:

Initial Velocity is 4 m/s

Explanation:

What is acceleration?

It is the change in velocity with respect to time, or the rate of change of velocity.

We can write this as:

a=\frac{\Delta v}{t}

Where

a is the acceleration

v is velocity

t is time

\Delta  is "change in"

For this problem , we are given

a = 1.2

t = 10

Putting into formula, we get:

a=\frac{\Delta v}{t}\\1.2=\frac{\Delta v}{10}\\\Delta v = 1.2*10\\\Delta v = 12

So, the change in velocity is 12 m/s

The change in velocity can also be written as:

\Delta v = Final  \ Velocity - Initial \ Velocity

It is given Final Velocity = 16, so we put it into formula and find Initial Velocity. Shown Below:

\Delta v = Final  \ Velocity - Initial \ Velocity\\12=16-Initial \ Velocity\\Initial \ Velocity = 16 - 12 = 4

hence,

Initial Velocity is 4 m/s

3 0
3 years ago
Read 2 more answers
Derive an expression for the acceleration of the car. Express your answer in terms of D and vt Determine the time at which the s
Bezzdna [24]

Answer:

V(car) = V(truck) at t = Dt/2

acceleration = v(car) = D/t^2

Explanation:

acceleration = v(car) = D/t^2

Since the average velocities must be the same, the car's final velocity must be twice the trunk velocity assuming the car start with zero velocity, since acceleration remain the same throughout the journey velocities at half-time point must be equal.

3 0
2 years ago
A woman is applying 300N/m2 of pressure on to door with her hand. Her hand has area of 0.02m2. Work out the force being applied​
never [62]

Answer:

6N

Explanation:

Given parameters:

Pressure applied by the woman  = 300N/m²

Area = 0.02m²

Unknown:

Force applied  = ?

Solution:

Pressure is the force per unit area on a body

        Pressure  = \frac{force}{area}

         Force  = Pressure x area

        Force  = 300 x 0.02  = 6N

8 0
2 years ago
A particle at 9 AM is moving towards the east at 4 ms At 12 noon, it changes its velocity and starts moving towards the north un
nexus9112 [7]

Answer:

Explanation:

Acceleration is the time rate of change of velocity.

Acceleration and velocity are vectors

If east and north are the positive directions, the east moving vector is reduced to zero and the north moving vector increases from zero to 4 m/s.

There are 3 hours or 10800 seconds between 10 AM and 1 PM

a1 = √((-4)² + 4²) / 10800 = (√32) / 10800 m/s² ≈ 4.2 x 10⁻⁴ m/s²

There are 14400 seconds between 10 AM and 2 PM

The velocity changes are still the same

a2 = √((-4)² + 4²) / 10800 = (√32) / 14400 m/s² ≈ 3.9 x 10⁻⁴ m/s²

7 0
2 years ago
While traveling from Boston to Hartford, Person A drives at a constant speed of 55 mph for the entire trip. Person B drives at 6
Ne4ueva [31]

Answer:

B will take 1.034 times the time of A from Boston to Hartford.

Explanation:

Let the distance from Boston to Hartford be S.

Person A drives at a constant speed of 55 mph for the entire trip,

Time taken by person A

             t_A=\frac{S}{55}

Person B drives at 65 mph for half the distance and then drives 45 mph for the second half of the distance.

Time taken by person B

            t_B=\frac{\frac{S}{2}}{65}+\frac{\frac{S}{2}}{45}=\frac{S}{130}+\frac{S}{90}=\frac{220S}{130\times 90}=\frac{11S}{585}

Ratio of time of arrival of B to A

                      \frac{t_B}{t_A}=\frac{\frac{11S}{585}}{\frac{S}{55}}=\frac{121}{117}=1.034

B will take 1.034 times the time of A from Boston to Hartford.

8 0
2 years ago
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