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2 years ago

Calculate the amount of energy produced in a nuclear reaction in which the mass defect is 0.187456 amu.

2 answers:

8 0

For nuclear reactions, we determine the energy dissipated from the process from the Theory of relativity wherein energy is equal to the mass defect times the speed of light. We calculate as follows:

E = mc^2 = 0.187456 (3x10^8)^2 = 1.687x10^16 J

Hope this answers the question.

pishuonlain [190]2 years ago

4 0

Answer:

$E = 174.6 MeV$

Explanation:

As we know that energy corresponding to the 1 amu mass is given as

$E = mc^2$

if m = 1 amu

we have

$E = 931.5 MeV$

so we will have

mass = 0.187456 amu

$E = (0.187456)(931.5)$

$E = 174.6 MeV$

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Elina [12.6K]

You are given an applied force of 110 n with an angle of 30° with the ground. Since the force is not perpendicular or parallel to the sled then you will have two components. These components are in sine and cosine form.

for parallel component
x = rcosβ
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x = 95.26

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y = rsinβ
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2 years ago

Read 2 more answers

You are using a hydrogen discharge tube and high quality red and blue light filters as the light source for a Michelson interfer

boyakko [2]

Answer:

final displacement = +24484.5 nm

Explanation:

The path difference when 158 bright spots were observed with red light (λ1 = 656.3 nm) is given as;

Δr = 2d2 - 2d1 = 150λ1

So, 2d2 - 2d1 = 150λ1

Dividing both sides by 2 to get;

d2 - d1 = 75λ1 - - - - eq1

Where;

d1 = distance between the fixed mirror and the beam splitter

d2 = position of moveable mirror from splitter when 158 bright spots are observed

Now, the path difference between the two waves when 114 bright spots were observed is;

Δr = 2d'2 - 2d1 = 114λ1

2d'2 - 2d1 = 114λ1

Divide both sides by 2 to get;

d'2 - d1 = 57λ1

Where;

d'2 is the new position of the movable mirror from the splitter

Now, the displacement of the moveable mirror is (d2 - d'2). To get this, we will subtract eq2 from eq1.

(d2 - d1) - (d'2 - d1) = 75λ1 - 57λ2

d2 - d1 - d'2 + d1 = 75λ1 - 57λ2

d2 - d'2 = 75λ1 - 57λ2

We are given;

(λ1 = 656.3 nm) and λ2 = 434.0 nm.

Thus;

d2 - d'2 = 75(656.3) - 57(434)

d2 - d'2 = +24484.5 nm

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2 years ago

Two cables of the same length are made of the same material, except that one cable has twice the diameter of the other cable. Wh

belka [17]

Answer: The same current flows through bth cables

Explanation:

Lets have a look to the next two equations

The Ohm´s V = I*R (1)

where:

V is voltage (potencial dfference) in volts

I is the electric current in ampers

R is the electric resistance

When a voltage is applied as the electrc load is not specified ( we have to assume is the same) the current will be the same

And in the other hand the resistance R =ρL/s

Where ρ is the resistivity of the conductor L the length and s square section of the conductor

If we assume that the smaller diameter cable is able to conduct the current then nothing happens. The point is that the capacity of conduction of current depend on the section of the cable (the area)

Tables exist where to find the capacity of each cable according to its diameter.

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2 years ago

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andrey2020 [161]

The correct answer is 17.24 m/s. You get the answer by subtracting the two heights of the tracks which are 36.5 and 10.8 m, and the answer is 25.7. Since you already know the height at which the kinetic energy will be coming from, you then divide the amount of weight the roller coaster has to the distance it needs to travel in order for you to determine the speed of the car. So that is, 4,357 kg and 25.7 m and the answer is 169 kg/m. Dividing it to the earth's gravity of 9.8 m/s you'll get 17.24 m/s.

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2 years ago

A sample of an unknown volatile liquid was injected into a Dumas flask (mflask = 27.0928 g, Vflask = 0.1040 L) and heated until

NNADVOKAT [17]

Answer:

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