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Naily [24]
2 years ago
13

Calculate the amount of energy produced in a nuclear reaction in which the mass defect is 0.187456 amu.

Physics
2 answers:
luda_lava [24]2 years ago
8 0
For nuclear reactions, we determine the energy dissipated from the process from the Theory of relativity wherein energy is equal to the mass defect times the speed of light. We calculate as follows:

E = mc^2 = 0.187456 (3x10^8)^2 = 1.687x10^16 J

Hope this answers the question.
pishuonlain [190]2 years ago
4 0

Answer:

E = 174.6 MeV

Explanation:

As we know that energy corresponding to the 1 amu mass is given as

E = mc^2

if m = 1 amu

we have

E = 931.5 MeV

so we will have

mass = 0.187456 amu

E = (0.187456)(931.5)

E = 174.6 MeV

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Read 2 more answers
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Zina [86]

Answer:

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Explanation:

<u>Concepts and Principles  </u>

The intensity at a distance r from a point source that emits waves of power P is given as:  

I=P/4π*r^2                         (1)

<u>Given Data</u>

f (frequency of the tuning fork) = 250 Hz

I_1 is the intensity at the source a distance r_1 = I m from the source.  

<u>Required Data</u>

- In part (a), we are asked to determine the intensity I_2 a distance r_2 = 4 in from the source.

- In part (b), we are asked to determine the distance from the tuning fork at which the intensity is a tenth of the intensity at the source.  

<u>solution:</u>

(a)  

According to Equation (1), the intensity a distance r is inversely proportional to the distance from the source squared:

I∝1/r^2

Set the proportionality:  

I_1/I_2=(r_2/r_1)^2                                 (2)

Solve for I_2 :  

I_2=I_1(r_2/r_1)^2  

I_2=0.0625 I_1

(b)  

Solve Equation (2) for r_2:  

r_2=(√I_1/I_2)*r_1

where I_2 = (1/10)*I_1:

r_2=(√I_1/1/10*I_1)*r_1

     =3.16 m

3 0
2 years ago
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