Joe pushes down the length of the handle of a 10.9 kg lawn spreader. The handle makes an angle of 45.3 ◦ with the horizontal. Jo
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Answer:
The acceleration of the rocket is 10 m/s².
Explanation:
Let the acceleration of the rocket be m/s².
Given:
Mass of the rocket is,
Thrust force acting upward is,
Acceleration due to gravity is,
Now, force acting in the downward direction is due to the weight of the rocket and is given as:
Now, net force acting on the rocket in upward direction is given as:
Therefore, from Newton's second law, net force acting on the rocket is equal to the product of mass and acceleration.
Therefore, the acceleration of the rocket is 10 m/s².
Starting from the angular velocity, we can calculate the tangential velocity of the stone:
Then we can calculate the angular momentum of the stone about the center of the circle, given by
where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.
Substituting the data of the problem, we find
Then we can calculate the angular momentum of the stone about the center of the circle, given by
where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.
Substituting the data of the problem, we find