A long, thin rod parallel to the y-axis is located at x = -1.0 cm and carries a uniform linear charge density of +1.0 nC/m. A se
cond long, thin rod parallel to the z-axis is located at x = +1.0 cm and carries a uniform linear charge density of -1.0 nC/m.
1 answer:
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Centripetal Force (Fcp) = ?
His arm length = Radius (R) = 0.75 m
Discus velocity = Linear Velocity (V) = 5 m/s
Discus mass (m) = 2 kg
Centripetal Acceleration (Acp) = V^2/R or W^2 x R
In this case i will use the V^2/R formula, because it uses the discus velocity (V).
Answer: Last option, 66 N.
His arm length = Radius (R) = 0.75 m
Discus velocity = Linear Velocity (V) = 5 m/s
Discus mass (m) = 2 kg
Centripetal Acceleration (Acp) = V^2/R or W^2 x R
In this case i will use the V^2/R formula, because it uses the discus velocity (V).
Answer: Last option, 66 N.
Answer:
Explanation:
Calculate the volume of the lead
Now calculate the bouyant force acting on the lead
This force will act in upward direction
Gravitational force on the lead due to its mass will act in downward direction
Hence the difference of this two force
If V is the volume submerged in the water then bouyant force on the bobber is
Equate bouyant force with the tension and gravitational force
Now Total volume of bobble is
=