A rubber ball with a mass 0.20 kg is dropped vertically from a height of 1.5 m above the floor. The ball bounces off of the floo
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<em>To determine the y component of velocity of a projectile </em><u><em>sine </em></u><em>operation is performed on the angle of launch.</em>
<u>Answer:</u> <em>sine</em>
<u>Explanation:</u>
Thus
The initial velocity u can be resolved along two directions.
Along the X direction initial velocity = u cos θ
Along y direction initial velocity= u sin θ
From the equation of motion
Thus velocity along x direction =u cos θ
Velocity along y direction = u sinθ -gt
Sign of g is negative.
Explanation:
It is given that,
Diameter of the semicircle, d = 45 m
Radius of the semicircle, r = 22.5 m
Speed of greyhound, v = 15 m/s
The greyhound is moving under the action of centripetal acceleration. Its formula is given by :
We know that,
Hence, this is the required solution.