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bonufazy [111]
1 year ago
5

Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t

his circle with the symbol for “initial position”. Move the object 5.0cm to the right and stop. Label this circle with the correct symbol for “final position.”  (A) What was the initial position of the object?     (B) What is the final position of the object?     (C) What is the distance traveled by the object?     (D) What is the displacement of the object?     (E) Of the three underlined quantities, which are numerically equal?
​

Physics
1 answer:
Viefleur [7K]1 year ago
6 0
It’s is D bc it is and idk you should do it
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the temperature of a 2.0-kg increases by 5*c when 2,000 J of thermal energy are added to the block. What is the specific heat of
nata0808 [166]
To calculate the specific heat capacity of an object or substance, we can use the formula

c = E / m△T

Where
c as the specific heat capacity,
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m as mass and
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3 0
1 year ago
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those a
garik1379 [7]

Answer:

T=2.94*10^-10  N/m.

Explanation:

Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.

To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?

l=length of the spider silk, 14cm

velocity of wave = √(T/μ)          

where T = tension and

μ = mass per unit length)

λ/2=l

for fundamental frequency λ/2 =14cm    

 (λ= wavelength of standing wave;  as there will be no node

   except the endpoints of silk strand)

               λ = 28 cm = 0.28 m

and since frequency * wavelength = speed of wave. we have,

                  150 * 0.28 = √(T/μ)                                        ..................(#)

now μ = mass/length = [volume * density]/length = [(length*area) * density] / length = area * density

         = [π * (10 * 10^(-6))²] * 1300  = 13π * 10^(-8).

now putting this in equation (#) we get

    150 * 0.28 = √(T/[13π * 10^(-8)]).

thus T = [13π * 10^(-8)] * (42)²     =  

2.94*10^-10  N/m.

6 0
1 year ago
A 16-Ω loudspeaker, an 8.0-Ω loudspeaker, and a 4.0-Ω loudspeaker are connected in parallel across the terminals of an amplifier
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Answer:

2.286 ohm

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6 0
2 years ago
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valentinak56 [21]

Answer:

\frac{kQ}{r^2} r^

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E= \frac{kQ}{r^2} r^

4 0
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