the temperature of a 2.0-kg increases by 5*c when 2,000 J of thermal energy are added to the block. What is the specific heat of
1 answer:
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Answer:
The force applied on the big piston is 1306.67 N
Explanation:
Given;
force applied on small piston, F₁ = 200 N
diameter of the small piston, d₁ = 4.37 cm
radius of the small piston, r₁ = d₁/2 = 2.185 cm
Area of the small piston, A₁ = πr₁² = π(2.185 cm)² = 15 cm²
Area of the big piston, A₂ = 98 cm²
The pressure of the piston is given by;
Where;
F₂ is the force on big piston
Therefore, the force applied on the big piston is 1306.67 N
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The magnitude is , the direction is into the page
Explanation:
From the question we are told that
The current is
The radius of arc bc is
The radius of arc da is
The length of segment cd and ab is =
The objective of the solution is to obtain the magnetic field
Generally magnetic due to the current flowing in the arc is mathematically represented as
Here I is the current
is the permeability of free space with a value of
r is the distance
Considering Arc da
Where is the angle the arc da makes with the center from the diagram its value is
Now substituting values into formula for magnetic field for da
Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to da is into the pages of the paper
Considering Arc bc
Substituting value
Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to bc is out of the pages of the paper
Since the line joining P to segment bc and da makes angle = 0°
Then the net magnetic field would be
Since then the direction of the net charge would be into the page
