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Fudgin [204]
1 year ago
11

The population in the United States in 2015 was 321 million people. It is projected to increase to 438 million people by the yea

r 2050.
If projections are true, the US population will increase _______% from 2015 to 2050.
Physics
2 answers:
Elza [17]1 year ago
6 0

Answer: So, en 2015 the population is 321 mill, and the prediction is it will increase to 438 mill in 2050.

If the projection is true, we can see that the relation between these numbers is 438/321 = 1.364

this means that the population in 2050 is 1.364 times the population in 2015. In percentage, the population in 2050 is 136.4% of the population in 2015, so the increment in population is 36.4%.

velikii [3]1 year ago
4 0

It increases by 35% ......

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An ambulance driving 35.0 m/s emits a sound wave with a wavelength of 80.0 centimeters. As it drives away from a hospital, which
katen-ka-za [31]

Apparent frequency heard by the staff: 389 Hz

Explanation:

The phenomenon described in this situation is called Doppler effect.

Doppler effect occurs when there is a source emitting a wave in relative motion with respect an observer. In such situation, the frequency of the wave as perceived by the observer ("apparent frequency") is shifted from the real frequency of the sound ("proper frequency"). In particular:

- The observer perceives a higher frequency if the source is moving towards them

- The observer perceives a lower frequency if the source is moving away from them

The formula to calculate the apparent frequency in the Doppler effect is

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the proper frequency

f' is the apparent frequency

v is the speed of the wave

v_o is the velocity of the observer (positive if they are moving towards the source, negative if moving away)

v_s is the velocity of the source (positive if it is moving away, negative if moving towards the observer)

First of all, in this problem we have to calculate the proper frequency of the sound wave emitted from the ambulance; we have:

v = 343 m/s (speed of sound wave)

\lambda=80 cm = 0.80 m (wavelength)

So the proper frequency is

f=\frac{v}{\lambda}=\frac{343}{0.80}=429 Hz

Now we can calculate the apparent frequency heard by the staff at the hospital when the ambulance moves away; we have:

v_s = +35.0 m/s (velocity of the ambulance)

v_o = 0 (velocity of the staff)

Substituting,

f'=\frac{343+0}{343+35}(429)=389 Hz

Learn more about frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

4 0
1 year ago
Two horses, Thunder and Misty, are accelerating a wagon 1.3 m/s2. The force of friction is 75 N. Thunder is pulling with a force
sasho [114]
Assumption both thunder and misty are pulling in same direction,
Net force= 1000N+800N-75N=1725N
Mass of wagon = 1725N/1.3ms^-2 = 1327kg
7 0
1 year ago
Read 2 more answers
f a car is speeding down a road at 40 miles/hour (mph), how long is the stopping distance D40 compared to the stopping distance
Oksana_A [137]

Answer:

D40 = 2.56 × D25

so number is 2.56 multiple of stopping distance @ 25 mph

Explanation:

given data

speed = 40 miles / hour

distance = D40

speed limit = 25 miles / hour

distance = D25

to find out

express number a multiple of stopping distance @ 25 mph

solution

we know here stopping distance is directly proportional to (speed)²

so here speed ratio is

initial speed = \frac{40}{25}

so initial speed = 1.6

so

stopping distance increase = (1.6)²

\frac{D40}{D25} = (1.6)²

\frac{D40}{D25} = 2.56

so here

D40 = 2.56 × D25

so number is 2.56 multiple of stopping distance @ 25 mph

5 0
1 year ago
A projectile is launched horizontally east at a speed of 29.4 M/s towards a wall 88.2 m away. What is the velocity of the projec
Drupady [299]

Time before projectile hits wall

= 88.2 m / 29.4 m/s = 3 seconds

Vertical velocity of projectile after three seconds

= 3*9.8 = 29.4 m/s

Horizontal velocity of projectile after three seconds, assuming no air resistance

= 29.4 m/s  (given)

Conclusion:

velocity of projectile when it hits the wall

= < 29.4, -29.4> m/s

= sqrt(29.4^2+29.4^2) m/s east-bound at 45 degrees below horizontal

= 41.58 m/s east-bound at 45 degrees below horizontal.

6 0
2 years ago
You throw a ball of mass 1 kg straight up. You observe that it takes 2.2 s to go up and down, returning to your hand. Assuming w
Elina [12.6K]

Answer:

10.791 m/s

5.93505 m

Explanation:

m = Mass of ball

v_f = Final velocity

v_i = Initial velocity

t_f = Final time

t_i = Initial time

g = Acceleration due to gravity = 9.81 m/s²

From the momentum principle we have

\Delta P=F\Delta t

Force

F=mg

So,

m(v_f-v_i)=mg(t_f-t_i)\\\Rightarrow v_i=v_f-g(t_f-t_i)\\\Rightarrow v_i=0-(-9.81)(1.1-0)\\\Rightarrow v_i=10.791\ m/s

The speed that the ball had just after it left the hand is 10.791 m/s

As the energy of the system is conserved

K_i=U\\\Rightarrow \dfrac{1}{2}mv_i^2=mgh\\\Rightarrow h=\dfrac{v_i^2}{2g}\\\Rightarrow h=\dfrac{10.791^2}{2\times 9.81}\\\Rightarrow h=5.93505\ m

The maximum height above your hand reached by the ball is 5.93505 m

5 0
2 years ago
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