Answer:
Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,
v = 2v
..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,
So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
(a) The diffraction decreases
The formula for the diffraction pattern from a single slit is given by:
where
is the angle corresponding to nth-minimum in the diffraction pattern, measured from the centre of the pattern
n is the order of the minimum
is the wavelength
a is the width of the opening
As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.
(b)
The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:
in this case we have
is the wavelength
is the width of the opening
Solving the equation, we find
So the angular spread of the central diffraction maximum is twice this angle:
(c)
Here we can apply the same formula used before, but this time the wavelength of the signal is
so the angle corresponding to the first minimum is
So the angular spread of the central diffraction maximum is twice this angle: