Two golf carts have horns that emit sound with a frequency of 394 Hz. The golf carts are traveling toward one another, each trav
1 answer:
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Answer:
Jari
Explanation:
The question requires to know who is traveling faster. This is done by comparing the gradients. The steeper the slope (high gradient), the faster the speed and vice versa.
From Jari's line, the starting point is (0, 0) and another point is (6, 7)
The gradient being change in y to change in x
Change in y=7-0=7
Change in x=6-0=6
Slope is 7/6
For Jade, first point is (0, 10) then another point is (6, 16)
Change in y=16-10=6
Change in x=6-0=6
Slope is 6/6=1
Clearly, 7/6 is greater than 6/6 or 1 hence Jari is faster than Jade
Answer:
Explanation:
You can consider that the force that acts over the proton is the same to the force over the electron. This is because the electric force is given by:
where E is the constant electric field between the parallel plates, and is the same for both electron and proton. Also, the charge is the same.
by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:
(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.
By doing the same for the electron you obtain:
we can equals these expressions for both proton and electron, because the forces qE are the same:
Heat engines were developed during industrial revolution.
Generally a heat engine contains three parts i.e source, sink and working substance.
The source of a heat engine is present at a higher temperature as compared to the sink. Due to the temperature difference, the heat will flow from source to sink through working substance.
Let us consider are the temperature of source and sink.
As the source is at higher temperature as compared to sink, heat will flow from source to sink.
are the heat provided by source and heat rejected to sink.
Hence, the work done by the working substance will be -
The efficiency of a heat engine is defined as the ratio of output to the input energy.
Here output = workdone [W]
Hence, the efficiency of a heat engine is calculated as -
This is the expression for the efficiency of heat engine.
Here, all the heat absorbed by the working substance can not be converted to desired output. The efficiency of a heat engine can not be 100 percent. Some amount of heat is lost in the form of sound and heat due to the friction which is produced due to the relative motion between various parts of the machine.
