EC_1 + EP_1 = EC2 + EP_2
EC_2 = 0
EC_2 = EP_1 - EP_2
EC_2 = mg(H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
Answer:
Final speed of car = 12 m/s
Explanation:
We have equation of motion v = u + at, where v is final velocity, u is initial velocity, a is acceleration and t is time.
a) A cart starts from rest and accelerates at 4.0 m/s² for 5.0 s
v = ?
u = 0 m/s
a = 4.0 m/s²
t = 5 s
v = u + at = 0 + 4 x 5 = 20 m/s
b) Then maintains that velocity for 10 s
v = ?
u = 20 m/s
a = 0 m/s²
t = 10 s
v = u + at = 20 + 0 x 10 = 20 m/s
c) Then decelerates at the rate of 2.0 m/s² for 4.0 s
v = ?
u = 20 m/s
a = -2.0 m/s²
t = 4 s
v = u + at = 20 + -2 x 4 = 12 m/s
Final speed of car = 12 m/s
6
Explanation:
The mechanical advantage is a factor that measures how input force increases using a machine.
A lever is a simple machine with the fulcrum at the center.
To calculate the mechanical advantage M.A of levers we use the expression below;
M. A =
= 
= input force
= output force
a is the distance of the input force from the fulcrum
b is the distance of the output force from the fulcrum
Given
a = 36cm
b = 6cm
M.A =
= 6
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Answer: 
Explanation:

Where;
a = acceleration
V2 = final velocity
V1 = initial velocity
t = time
If John runs 1.0 m/s first, we assume this is V1. He accelerates to 1.6 m/s; this is V2.



Answer:
a=
Explanation:
The net force,
of the box is expressed as a product of acceleration and mass hence
where m is mass and a is acceleration
Making a the subject, a= 
From the attached sketch,
∑
where
is frictional force and
is horizontal angle
Substituting ∑
as
in the equation where we made a the subject
a= 
Since we’re given the value of F as 240N,
as 41.5N,
as
and mass m as 30kg
a= 